What is the sodium ion molarity in 250 mL of a Normosol-R fluid replacement containing 31 mmoles of Na+ ? Express your answer to two significant figures and include the appropriate units. HÀ ?
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![**Question:**
What is the sodium ion molarity in 250 mL of a Normosol-R fluid replacement containing 31 mmoles of Na⁺?
**Instructions:**
Express your answer to two significant figures and include the appropriate units.
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**Solution Overview:**
To calculate molarity, use the formula:
\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \]
Given:
- 31 mmoles of Na⁺
- 250 mL of solution
**Step-by-Step Solution:**
1. Convert millimoles to moles:
\[ 31 \text{ mmoles} = 31 \times 10^{-3} \text{ moles} \]
2. Convert mL to L:
\[ 250 \text{ mL} = 0.250 \text{ L} \]
3. Calculate molarity:
\[ \text{Molarity (M)} = \frac{31 \times 10^{-3} \text{ moles}}{0.250 \text{ L}} \]
4. Simplify to find the molarity:
\[ \text{Molarity (M)} = 0.124 \text{ M} \]
**Final Answer:**
The sodium ion molarity is 0.12 M.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4765ee54-4bf1-4968-aef6-4d5dd9268751%2F1f625f96-29be-42a7-bc2f-33a5a8000955%2F1i82g3h_processed.png&w=3840&q=75)
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