### The RDT 3.0 ProtocolAs we learned in class, the rdt3.0 protocol reliably transfers data from sender to receiver over a channel that can corrupt, lose and delay (but not reorder) packets. The rdt 3.0 sender and receivers (taken verbatim from the textbook and from our class notes) are shown below FYI. Recall that the sender starts in state "Wait for call 0 from above", and the receiver starts in state "Wait for 0 from below".#### RDT 3.0 Sender:The diagram represents the sender's finite state machine (FSM) with the following states and transitions:1. **Wait for call 0 from above**: - `rdt_send(data)` - Creates a packet with sequence number 0 and checksum. - Sends the packet and starts a timer. 2. **Wait for ACK 0**: - Receives packet (`rdt_rcv(rcvpkt)`) - If packet is neither corrupted nor ACK 0 → State remains - If packet is corrupted or ACK is not 1 → Resend packet and reset timer - If packet is ACK 0 → Stop timer and move to next state. 3. **Wait for call 1 from above**: - Same as state 1 but with sequence number 1. 4. **Wait for ACK 1**: - Same as state 2 but with ACK 1 validation.#### RDT 3.0 Receiver:The diagram represents the receiver's FSM with the following states and transitions:1. **Wait for 0 from below**: - Receives packet (`rdt_rcv(rcvpkt)`) - If valid packet with sequence number 0 (not corrupted and having sequence number 0) → Extracts data, delivers data and sends ACK 0. Moves to next state. - If corrupted or sequence number is not 0 → Sends ACK 1. 2. **Wait for 1 from below**: - Receives packet (`rdt_rcv(rcvpkt)`) - If valid packet with sequence number 1 (not corrupted and having sequence number 1) → Extracts data, delivers data and sends ACK 1. Moves to next state. - If corrupted or sequence number is not 1 → Sends ACK 0.Below the FSM diagrams, there is

This is very simple. The correct answer is option c) which is 1 Explanation…

Answered: What is the sequence number on the…

What is the sequence number on the packet sent by the sender at time t₂? (Note: there is only one correct answer below).

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (a) What will be the sequence number of the third TCP handshake signal send from PC to webserver?…
SMTP (Simple Mail Transfer Protocol) is the standard protocol for transferring mail between hosts over Transmission Control Protocol (TCP). A TCP connection is set up between a user agent and a server program. The server listens on TCP port 25 for incoming connection requests. The user end of the connection is on a TCP port number above 1023. Suppose you wish to build a packet filter rule set allowing inbound and outbound SMTP traffic. You generate the following rule set: Rule Direction Src Addr Dest Addr Protocol Dest Port Action A In External Internal TCP 25 Permit B Out Internal External TCP > 1023 Permit C Out Internal External TCP 25 Permit D In External Internal TCP > 1023 Permit E Either Any Any Any Any Deny Describe the effect of each rule.
SMTP (Simple Mail Transfer Protocol) is the standard protocol for transferring mail between hosts over Transmission Control Protocol (TCP). A TCP connection is set up between a user agent and a server program. The server listens on TCP port 25 for incoming connection requests. The user end of the connection is on a TCP port number above 1023. Suppose you wish to build a packet filter rule set allowing inbound and outbound SMTP traffic. You generate the following rule set: Rule Direction Src Addr Dest Addr Protocol Dest Port Action A B C D E In Out Out In Either External Internal Internal External Internal External External Internal Any Any a. Describe the effect of each rule. TCP TCP TCP TCP Any 25 > 1023 25 > 1023 Permit Permit Permit Permit Any Deny A
SMTP (Simple Mail Transfer Protocol) is the standard protocol for transferring mail between hosts over Transmission Control Protocol (TCP). A TCP connection is set up between a user agent and a server program. The server listens on TCP port 25 for incoming connection requests. The user end of the connection is on a TCP port number above 1023. Suppose you wish to build a packet filter rule set allowing inbound and outbound SMTP traffic. You generate the following rule set: Rule Direction Src Addr Dest Addr Protocol Dest Port Action A B C D E In Out Out In Either External Internal Internal External Internal External Any External Internal Any TCP TCP TCP TCP Any 25 > 1023 25 > 1023 Permit Permit Permit Permit Any Deny Someone from the outside world (10.1.2.3) attempts to open a connection from port 5150 on a remote host to the Web proxy server on port 8080 on one of your local hosts (172.16.3.4), in order to carry out an attack. Typical packets are as follows: Scenario Direction 3 4 In…
5. Expand the information on the Transmission Control Protocol for this packet in the Wireshark “Details of selected packet” window (see Figure 3 in the lab writeup) so you can see the fields in the TCP segment carrying the HTTP message. What is the destination port number (the number following “Dest Port:” for the TCP segment containing the HTTP request) to which this HTTP request is being sent?
please help me 3-bit
Write a program in C that prints the default TCP, UDP, and SCTP send and receive buffer sizes.
For NAT Network Address Translation Scenario: Jenny Bello is a small business owner selling and making customized computer peripherals. She has been finding it difficult to track her sales and inventories, however recently after an expert's advice, she adopted a Point of Sale (PoS) server. So, she can now track her sales and inventories at the store. However, she ran into another issue, the server can only be accessed within the store, because it has been assigned a private IPv4 address, it is not publicly accessible via the Internet. a) Why is not having the PoS server accessible over the Internet a problem for the business? b) What caused this problem? c) Propose a solution for the problem and explain how the solution works.
Write a code in C that prints the following: Prints default TCP send and receive buffer sizes.Prints default UDP send and receive buffer sizes.Prints default SCTP send and receive buffer sizes.
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I am analysing a pcap file using Python and wireshark. Currently, I have it counting the number of packets I would like to count the number of SYN and ACK packets with this function? My main piece of code thus far is n is an int please show me how to write the code for this.
Please solve it correctly and please provide explanation of your answers. Please answer parts g, h and i. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. g) The second segment from webserver was corrupted. So the PC…