What is the RMS voltage from a sinusoidal AC source that has an output V = 150 sin(21ft)? (Enter answer as an integer. Do not enter unit.)

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Chapter1: Units, Trigonometry. And Vectors
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**Question:** What is the RMS voltage from a sinusoidal AC source that has an output \( V = 150 \sin(2\pi ft) \)? (Enter answer as an integer. Do not enter unit.)

**Additional Note:** Moving to another question will save this response.

**Explanation:**

- **Expression for AC Voltage:**
  The expression given is \( V = 150 \sin(2\pi ft) \), where:
  - 150 is the peak voltage (\( V_{\text{peak}} \)).
  - \(\sin(2\pi ft)\) represents the sinusoidal function of time.

- **Root Mean Square (RMS) Voltage:**
  \( V_{\text{RMS}} \) for a sinusoidal voltage is calculated using the formula:
  \[
  V_{\text{RMS}} = \frac{V_{\text{peak}}}{\sqrt{2}}
  \]

- **Calculation:**
  Substituting the given peak voltage:
  \[
  V_{\text{RMS}} = \frac{150}{\sqrt{2}} \approx 106
  \]

Enter the value 106 as the integer answer.
Transcribed Image Text:**Question:** What is the RMS voltage from a sinusoidal AC source that has an output \( V = 150 \sin(2\pi ft) \)? (Enter answer as an integer. Do not enter unit.) **Additional Note:** Moving to another question will save this response. **Explanation:** - **Expression for AC Voltage:** The expression given is \( V = 150 \sin(2\pi ft) \), where: - 150 is the peak voltage (\( V_{\text{peak}} \)). - \(\sin(2\pi ft)\) represents the sinusoidal function of time. - **Root Mean Square (RMS) Voltage:** \( V_{\text{RMS}} \) for a sinusoidal voltage is calculated using the formula: \[ V_{\text{RMS}} = \frac{V_{\text{peak}}}{\sqrt{2}} \] - **Calculation:** Substituting the given peak voltage: \[ V_{\text{RMS}} = \frac{150}{\sqrt{2}} \approx 106 \] Enter the value 106 as the integer answer.
Expert Solution
Step 1

Output voltage is given by : 

V = 150Sin(2πft) 

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