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An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by V = Vo sin(2xft) and the source frequency is 14.0 Hz, at what time t will the current flowing in this circuit be 54.0% of the peak current? 0.011378 Note that the voltage in this AC circuit is a sine function. Did you use the correct units for the argument of the sine function? ms Additional Materials O Reading

An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by V = Vo sin(2xft) and the source frequency is 14.0 Hz, at what time t will the current flowing in this circuit be 54.0% of the peak current? 0.011378 Note that the voltage in this AC circuit is a sine function. Did you use the correct units for the argument of the sine function? ms Additional Materials O Reading

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An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by V = Vo sin(2xft) and the source frequency is 14.0 Hz, at what time t will the current flowing in this circuit be 54.0% of the peak current? 0.011378 Note that the voltage in this AC circuit is a sine function. Did you use the correct units for the argument of the sine function? ms Additional Materials O Reading
Transcribed Image Text:An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by V = Vo sin(2xft) and the source frequency is 14.0 Hz, at what time t will the current flowing in this circuit be 54.0% of the peak current? 0.011378 Note that the voltage in this AC circuit is a sine function. Did you use the correct units for the argument of the sine function? ms Additional Materials O Reading
Expert Solution
Step 1

Given source frequency (f) is 14 Hz,

The value of voltage V in the circuit is,

V=V∘sin(2π×f×t)

where V is the voltage at the time t, V∘ is the peak value of voltage, f is the frequency and t is the time.

As given, the circuit is consisting of resistance R in series connection to a voltage source.

Thus, current in the circuit by using Ohm's law can be defined as,

I = VR

Substituting the value of the voltage at time t in the above equation, 

I = V∘Rsin(2π×f×t)=I∘sin(2π×f×t)

where, I∘=V∘R is the peak value of current in the circuit.

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