Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![The average kinetic energy of the molecules in a gas sample depends only on the temperature, \( T \). However, given the same kinetic energies, a lighter molecule will move faster than a heavier molecule, as shown in the equation for rms speed:
\[
\text{rms speed} = \sqrt{\frac{3RT}{\mathcal{M}}}
\]
where \( R = 8.314 \, \text{J/(mol}\cdot\text{K)} \) and \( \mathcal{M} \) is molar mass in kilograms per mole. Note that a joule is the same as a kilogram-meter squared per second squared (kg\(\cdot\)m\(^2\)/s\(^2\)).
**Question 1:**
What is the rms speed of \( \text{F}_2 \) molecules at 303 K?
**Answer Box:**
rms speed: \_\_\_\_\_\_\_\_\_\_\_\_ m/s
---
**Question 2:**
What is the rms speed of He atoms at 303 K?
**Answer Box:**
rms speed: \_\_\_\_\_\_\_\_\_\_\_\_ m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4cbada35-3122-4a6c-a25c-246bca0ae236%2Fbde05316-f603-41ac-8801-95caae0678fe%2Fwq362iv_processed.png&w=3840&q=75)
Transcribed Image Text:The average kinetic energy of the molecules in a gas sample depends only on the temperature, \( T \). However, given the same kinetic energies, a lighter molecule will move faster than a heavier molecule, as shown in the equation for rms speed:
\[
\text{rms speed} = \sqrt{\frac{3RT}{\mathcal{M}}}
\]
where \( R = 8.314 \, \text{J/(mol}\cdot\text{K)} \) and \( \mathcal{M} \) is molar mass in kilograms per mole. Note that a joule is the same as a kilogram-meter squared per second squared (kg\(\cdot\)m\(^2\)/s\(^2\)).
**Question 1:**
What is the rms speed of \( \text{F}_2 \) molecules at 303 K?
**Answer Box:**
rms speed: \_\_\_\_\_\_\_\_\_\_\_\_ m/s
---
**Question 2:**
What is the rms speed of He atoms at 303 K?
**Answer Box:**
rms speed: \_\_\_\_\_\_\_\_\_\_\_\_ m/s
Expert Solution

Step 1:- Calculation of rms speed of F2
• Thus, the rms speed of F2 molecules at 303 K is 446 m/s in correct number of significant figures.
Step by step
Solved in 2 steps with 2 images

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