A sample of hydrogen gas at a pressure of 903 torr and a temperature of 26.9°C, occupies a volume of 692 mL. If the gas is allowed to expand at constant temperature until its pressure is 633 torr, the volume of the gas sample will be | mL.

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Chapter1: Chemical Foundations
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**Problem Statement:**

A sample of hydrogen gas at a pressure of 903 torr and a temperature of 26.9°C occupies a volume of 692 mL. If the gas is allowed to expand at constant temperature until its pressure is 633 torr, the volume of the gas sample will be ______ mL.

**Explanation:**

This problem involves the relationship between the pressure and volume of a gas at constant temperature, described by Boyle's Law. Boyle's Law states that the pressure of a given mass of gas is inversely proportional to its volume at a constant temperature:

\[ P_1 V_1 = P_2 V_2 \]

Where:
- \( P_1 \) = initial pressure (903 torr)
- \( V_1 \) = initial volume (692 mL)
- \( P_2 \) = final pressure (633 torr)
- \( V_2 \) = final volume (unknown)

By rearranging the formula to solve for \( V_2 \), we get:

\[ V_2 = \frac{P_1 V_1}{P_2} \]

Substituting the given values:

\[ V_2 = \frac{903 \, \text{torr} \times 692 \, \text{mL}}{633 \, \text{torr}} \]

Calculating the result:

\[ V_2 \approx 987 \, \text{mL} \]

Therefore, the volume of the gas sample when it expands at the constant temperature until its pressure is 633 torr will be approximately 987 mL.
Transcribed Image Text:**Problem Statement:** A sample of hydrogen gas at a pressure of 903 torr and a temperature of 26.9°C occupies a volume of 692 mL. If the gas is allowed to expand at constant temperature until its pressure is 633 torr, the volume of the gas sample will be ______ mL. **Explanation:** This problem involves the relationship between the pressure and volume of a gas at constant temperature, described by Boyle's Law. Boyle's Law states that the pressure of a given mass of gas is inversely proportional to its volume at a constant temperature: \[ P_1 V_1 = P_2 V_2 \] Where: - \( P_1 \) = initial pressure (903 torr) - \( V_1 \) = initial volume (692 mL) - \( P_2 \) = final pressure (633 torr) - \( V_2 \) = final volume (unknown) By rearranging the formula to solve for \( V_2 \), we get: \[ V_2 = \frac{P_1 V_1}{P_2} \] Substituting the given values: \[ V_2 = \frac{903 \, \text{torr} \times 692 \, \text{mL}}{633 \, \text{torr}} \] Calculating the result: \[ V_2 \approx 987 \, \text{mL} \] Therefore, the volume of the gas sample when it expands at the constant temperature until its pressure is 633 torr will be approximately 987 mL.
Expert Solution
Step 1

According to ideal gas law,

PV = nRT

where P = pressure

V = volume

n = moles

R = gas constant

T = temperature in K = T in °C + 273

Since the temperature is given constant. And also no change in moles of gas happening 

Hence n and T are constant

Hence PV = nRT = constant 

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