What is the resolving power of a 25-cm (10-in.) telescope at a wavelength of 550 nm (in the middle of the visual band)?
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A: Given- λ=550 nm=550×10-9 m
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Q: What is the diffraction limit of a 4 m telescope observing light at 550 nm? Answer in arc seconds
A: diameter of telescope(D)=4m wavelength(λ)=550nm=550×10-9 m formula diffraction limit(θ)=1.22λD
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A: The expression for the angular resolution ,limit due to diffraction is, θ=1.22λD
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Q: Part 5 of 5 We can use our new diameter to determine the resolving power of this telescope. x = 2.06…
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Q: (diameter LGP = Area = t 2
A: The Light Gathering Power is calculated as : LGP = Area = π (diameter/2)2
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A: The expression for the resolving power is,
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A: The resolving power of a telescope is given by, R = 1∆θ= d1.22 λ where ∆θ is the angular resolution…
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A: Given, Diameter D=2m wavelength =550nm x=5.5m
Q: want a telescope that would allow you to see distinguishing features as small as 3.5 km on the Moon…
A: GivenL=3.5kmr=384000 kmλ=550 nm=550×10−9m
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