1)a) What is the repulsive force between two pith balls that are 8.00 cm apart and have equal chargesof -30.0 nC? (Recall that a conventionally unit of charge is coulomb. 1 nC refers to (10-Coulomb)b) What magnitude point charge creates a 10, 000N/C electric field at a distance of 0.250 m? (b) Howlarge is the field at 10.0 m?c) What are the signs of the charges on the particles in the following setup?XXX X BinXxXХаXXXXX XX b Xсх

Since you have asked multiple unrelated questions, only the first question is answered here. Please repost the remaining questions separately. Given: The Charges on each pith ball: q1=q2=q=-30 nC=-30×10-9 C Distance between the balls: r=8 cm =8×10-2 mthe force acting between the pith balls is given by: F=kq1q2r2 k is the Coulomb's constantor, F=kq2r2 q1=q2=qor, F=9×109×-30×10-928×10-22 N k=9×109 Nm2/C2or, F=126.56×10-5 N The sign is positive, thus it represents a repulsive force.

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) What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of - 30.0 nC? (Recall that a conventionally unit of charge is coulomb. 1 nC refers to (10-⁹Coulomb)

) What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of - 30.0 nC? (Recall that a conventionally unit of charge is coulomb. 1 nC refers to (10-⁹Coulomb)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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been stuck on this question for a while, would appreciate help If a particulate, with a mass of 2.1 x 10-5 kg, acquires a charge of 3.2 μC , the electrical force on the particulate, due to the electric field is: a 4.3 x 10-2 N b 4.3 N c 4.3 x 106 N d 4.2 x 1011 N explanation would be highly appreciated!