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What is the proper equation for calculating the low frequency break point due to the capacitor CC for this BJT amplifier. (note: Ro = ro // RC) 9 +Vcc R1 82 ka 2.2 ka 0.2 μF Cs Rs 800 0.5 μ F RL 5.2 ka R2 RE CE 10μ 12.5 ka 1.1 ka 1 B) fLC= RLJCC D) ÍLC= 27{RC RLJCC 1 A) fLC= 27 Ro+ 27(ro + RL)CC 1 C) fLC=2TRCCC 2RC | RL)C

What is the proper equation for calculating the low frequency break point due to the capacitor CC for this BJT amplifier. (note: Ro = ro // RC) 9 +Vcc R1 82 ka 2.2 ka 0.2 μF Cs Rs 800 0.5 μ F RL 5.2 ka R2 RE CE 10μ 12.5 ka 1.1 ka 1 B) fLC= RLJCC D) ÍLC= 27{RC RLJCC 1 A) fLC= 27 Ro+ 27(ro + RL)CC 1 C) fLC=2TRCCC 2RC | RL)C

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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What is the proper equation for calculating the low frequency break point due to the capacitor CC for this BJT amplifier. (note: Ro = ro // RC) 9 +Vcc R1 82 ka 2.2 ka 0.2 μF Cs Rs 800 0.5 μ F RL 5.2 ka R2 RE CE 10μ 12.5 ka 1.1 ka 1 B) fLC= RLJCC D) ÍLC= 27{RC RLJCC 1 A) fLC= 27 Ro+ 27(ro + RL)CC 1 C) fLC=2TRCCC 2RC | RL)C
Transcribed Image Text:What is the proper equation for calculating the low frequency break point due to the capacitor CC for this BJT amplifier. (note: Ro = ro // RC) 9 +Vcc R1 82 ka 2.2 ka 0.2 μF Cs Rs 800 0.5 μ F RL 5.2 ka R2 RE CE 10μ 12.5 ka 1.1 ka 1 B) fLC= RLJCC D) ÍLC= 27{RC RLJCC 1 A) fLC= 27 Ro+ 27(ro + RL)CC 1 C) fLC=2TRCCC 2RC | RL)C
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