What is the potential energy of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.) Express your answer with the appropriate units.
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A: q1= 8.1 x 10-6 C ( according to pasted photo by you)
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A: The expression for electric potential energy is, UE=kq1q2r (I)…
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- Three equal 1.20 mC point charges are placed at the corners of an equilateral triangle with sides 0.400 m long. What is the potential energy of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.)Two parallel plates 10 cm on a side are given equal and opposite charges of magnitude 5.0 × 10−9 C. The plates are 1.5 mm apart. What is the potential difference between the plates?Three point charges q1 = +2.7µC, q2 = −3.4µC and q3 = −1.6µC initially are infinitely far apart. They are then brought together and placed at the corners of an equilateral triangle. Each side has a length of 40 cm. Determine the total electric potential energy of these group of charges The final answer should be Example: 0.06N or 6.0x10^-2 N must be expressed to 60x10^-3 N or 60mN
- Four objects with positive charges of +1.0 x 10-5 C are placed at the four vertices of a45° rhombus with sides of length 2.0 m.(a) Calculate the electric potential at the centre of the rhombus (this is located where thediagonals intersect). b) Calculate the electric potential energy a charge of +3.0 x 10-5 C would have if placed atthe centre of the rhombus.Two protons are 3.9 x 10-5 m apart. What is the electrical potential energy between the two charges? Group of answer choices 9.46 x 10^-24 J 4.76 x 10^-24 J 4.95 x 10^-24 J 5.91 x 10^-24 J 6.58 x 10^-24 JThree equal point charges, each with charge 1.40 μC , are placed at the vertices of an equilateral triangle whose sides are of length 0.600 mm . What is the electric potential energy U of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.)
- A point charge of 5.4 x 10-6 is held in place (initially at rest) at the origin. If a second point charge of -5.9 x 10-6 C is moved from its initial location of (0.48, 0) m to a final location of (1.3, 0) m, what is the change in potential energy of the system. Assume that the 2 point charges are isolated.There is a distribution of charges as evidenced below where q₁ = +5.0 nC and q2 = -3.0 nC. If a third charge of magnitude 2.00 nC is placed between the first two charges at a distance of 15.00 cm from the origin along the x-axis, what is the potential energy of the system? You may assume that the third charge originated from an infinite distance away. Now if we wanted the potential energy of the system to be zero, where should the third charge be placed (hint: you will need to simplify and then solve a quadratic or you can use solver in excel)? Y 91 93 x=15.00 cm 92 x=30.00 cm XYou'll learn that the potential energy of two electric charges is inversely proportional to the distance between them. Two charges 30 nm apart have 1.0 J of potential energy. What is their potential energy if they are 22 nm apart? Express your answer with the appropriate units.