Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![### Determining the pH of a 2.8 M Solution of HClO₄
In this lesson, we will calculate the pH of a 2.8 M solution of perchloric acid (HClO₄).
#### Problem Statement:
**What is the pH of a 2.8 M solution of HClO₄?**
#### Calculation:
pH is calculated using the formula:
\[ \text{pH} = -\log[H^+] \]
For a strong acid like HClO₄, it completely dissociates in water:
\[ \text{HClO}_4 \rightarrow H^+ + \text{ClO}_4^- \]
This means the concentration of \( H^+ \) ions is equal to the initial concentration of the perchloric acid solution.
Given:
- The concentration of HClO₄ is 2.8 M.
So,
\[ [H^+] = 2.8 \, \text{M} \]
Using the pH formula:
\[ \text{pH} = -\log(2.8) \]
Therefore, the pH of the 2.8 M solution of HClO₄ is:
\[ \text{pH} = \boxed{pH = -\log(2.8)} \]
You can compute this using a scientific calculator.
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This exercise is a fundamental practice in understanding the relationship between the concentration of a strong acid and its pH value.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc325aa0-3b4d-4100-824a-15814ab6662e%2Fcdb36e8e-833e-49cd-a60b-a79d968f2c4a%2F5bjp4me_processed.jpeg&w=3840&q=75)
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