What is the overall order of the following reaction, given the rate law? NO(3) + O3ls) → NO23) + O23) Rate = k[NO|[03) O 15 order O 3rd order O 1st order Oth order O 2nd order
What is the overall order of the following reaction, given the rate law? NO(3) + O3ls) → NO23) + O23) Rate = k[NO|[03) O 15 order O 3rd order O 1st order Oth order O 2nd order
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Need help it’s not zero order
![### Determining the Overall Order of a Reaction
**Question:**
What is the overall order of the following reaction, given the rate law?
\[ \text{NO}(g) + \text{O}_3(g) \rightarrow \text{NO}_2(g) + \text{O}_2(g) \]
\[ \text{Rate} = k[\text{NO}][\text{O}_3] \]
**Options:**
1. \( \frac{1}{2} \) order
2. 3rd order
3. 1st order
4. 0th order
5. 2nd order
**Explanation:**
To determine the overall order of a reaction, we sum the exponents of the concentration terms in the rate law.
From the given rate law:
\[ \text{Rate} = k[\text{NO}][\text{O}_3] \]
The exponent of \([\text{NO}]\) is 1 and the exponent of \([\text{O}_3]\) is also 1.
Therefore, the overall order of the reaction is:
\[ 1 + 1 = 2 \]
**Correct Answer:**
- 2nd order](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F560885b1-95a6-46a1-8479-9132da42c8bd%2F0162263b-9569-4cc3-a9f3-16b8e446d5a2%2Fwe20voq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Determining the Overall Order of a Reaction
**Question:**
What is the overall order of the following reaction, given the rate law?
\[ \text{NO}(g) + \text{O}_3(g) \rightarrow \text{NO}_2(g) + \text{O}_2(g) \]
\[ \text{Rate} = k[\text{NO}][\text{O}_3] \]
**Options:**
1. \( \frac{1}{2} \) order
2. 3rd order
3. 1st order
4. 0th order
5. 2nd order
**Explanation:**
To determine the overall order of a reaction, we sum the exponents of the concentration terms in the rate law.
From the given rate law:
\[ \text{Rate} = k[\text{NO}][\text{O}_3] \]
The exponent of \([\text{NO}]\) is 1 and the exponent of \([\text{O}_3]\) is also 1.
Therefore, the overall order of the reaction is:
\[ 1 + 1 = 2 \]
**Correct Answer:**
- 2nd order
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