What is the output of this code? (scroll to the left and right to make sure you have viewed the whole code) *This question will be auto-graded. Be careful about spacing. public class Question public static void main(String[] args) { int[][] a {(1,23,72, 20). (345, 42, 54), (61, 76, 87, 99,78,40 ) ): int sum1 access (a): int [11b (1, 23,34,56,78, 98, 29, 30). (223, 345, 467, 52 ). ( 15, 25, 55,75,87). access (b); int sum2 System.out.print (sum1); System.out.println(sum2); } public static int access (int[][] a) ( return a[0][a[0).length 11+ ala.length 11lala.length 1).length - 1]: - -
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- Multiples(): Takes an int (n) as parameter and prints first 10 multiples n in a single line using for loop. Example: 5 5,10,15,20,25,30,35,40,45,50 class Main {public static void main(String[] args) {}}//Assignment 06 */public static void main[](String[] args) { String pass= "ICS 111"; System.out.printIn(valPassword(pass));} /* public static boolean valPassword(String password){ if(password.length() > 6) { if(checkPass(password) { return true; } else { return false; } }else System.out.print("Too small"); return false;} public static boolean checkPass (String password){ boolean hasNum=false; boolean hasCap = false; boolean hasLow = false; char c; for(int i = 0; i < password.length(); i++) { c = password.charAt(1); if(Character.isDigit(c)); { hasNum = true; } else if(Character.isUpperCase(c)) { hasCap = true; } else if(Character.isLowerCase(c)) { hasLow = true; } } return true; { return false; } }DebugEight4: Here is the code that needs to be debugged, I fixed some but it will not display the words in reverse at the end: // Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { public static void main(String[] args) { Scanner input = new Scanner(System.in); int x = 0, y; String array[] = new String[100]; String entry; final String STOP = "XXX"; StringBuffer message = new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter " + STOP + " when you want to stop"); entry = input.next(); } for(y = x - 1; y > 0; ++y) {…
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?
- 40.|Asiacell docs.google.com/forms :D yuustivi بل اجابة هذا السؤال بشكل PDF Describe the difference between tl .following two progran class Progarml { public static void main(String[] args) { int[] a = {1, 2}: q3(a); System.out.println( a[0]+ " " +a[1]);} class Program2 { public static void main(String[] args) { int[] a = {1, 2}; q3(a[0], a[ 1]); System.out.println(a[0]+ " "+ a[1]);} static void swap(int[] a) { int t = a[0]: a[0] = a[1]: a[1] = t:} static void q3(int n1, int n2) { int t =n1; nl = n2; n2 = t;} إضافة ملف 4 صفحة 3 من التالي Es ل كلمات المرور عبر نماذج Google مطلقًا.Write an application that counts by five from 5 through 500 inclusive, and that starts a new line after every multiple of 50 (50, 100, 150, and so on). public class CountByFives { public static void main (String args[]) { // Write your code here } }Exercise Objectives Problem Description Write a program that reads a string and mirrors it around the middle character. Examples: abcd becomes cdab. abcde becomes deCab AhmadAlami becomes AlamiAhmad Page 1 of 2 Your program must: • Implement function void reflect (char* str) which receives a string (array of characters) and mirrors it. This function does not print anything. • Read from the user (in main()) a string and then print the string after calling function reflect(). • Use pointers and pointer arithmetic only. The use of array notation and/or functions from the string.h library is not allowed.
- // Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { publicstaticvoidmain(String[] args) { Scanner input =newScanner(System.in); int x =0, y; String array[] =newString[100]; String entry; finalString STOP =XXX; StringBuffer message =new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter "+STOP+" when you want to stop"); entry = input.next(); } for(y = x -1; y >0; ++y) { message.append(array[y]); message.append("\n"); } System.out.println(message) }Instructions Insurance.java >- Terminal + 1 import java.util.Scanner; sandbox $ 0 2 class Insurance { The Harrison Group Life Insurance company computes public static void main (String args[]) { // Write your code here annual policy premiums based on the age the customer 4 turns in the current calendar year. The premium is } computed by taking the decade of the customer's age, adding 15 to it, and multiplying by 20. 7 public static int calculatePremium(int curr, int birth) { 8 // Write your code here } For example, a 34-year-old would pay $360, which is calculated by adding the decades (3) to 15, and then 10 } 11 multiplying by 20. Write an application that prompts a user for the current year then a birth year. Pass both to a method that calculates and returns the premium amount, and then display the returned amount. An example of the program is shown below: Enter the current year >> 2020 Enter the birth year >> 2001 The premium is $320 Grading Write your Java code in the area on the…SEE MORE QUESTIONS