**Question:** What is the output of the following code?```pythonsum = 0for i in range(1, 10): if i % 3: continue sum += iprint(sum)```**Explanation:**1. **Initialization:** ```python sum = 0 ``` This line initializes a variable `sum` to 0.2. **For Loop:** ```python for i in range(1, 10): ``` This loop iterates over the integers from 1 to 9 (inclusive at start, exclusive at end).3. **Condition and Continue:** ```python if i % 3: continue ``` This condition checks if the current value of `i` is not a multiple of 3 (`i % 3` evaluates to `True` if `i` is not a multiple of 3). If this condition is true, the `continue` statement is executed, which skips the rest of the code inside the loop for the current iteration.4. **Sum Accumulation:** ```python sum += i ``` This line adds the value of `i` to `sum`, but only if `i` is a multiple of 3 (because the non-multiples of 3 are skipped by the `continue` statement).5. **Printing the Result:** ```python print(sum) ``` Finally, it prints the value of `sum`.**Detailed Steps of Execution:**- For `i = 1`: `1 % 3` is `True` -> `continue` (sum remains 0)- For `i = 2`: `2 % 3` is `True` -> `continue` (sum remains 0)- For `i = 3`: `3 % 3` is `False` -> `sum += 3` (sum becomes 3)- For `i = 4`: `4 % 3` is `True` -> `continue` (sum remains 3)- For `i = 5`: `5 % 3` is `True` -> `continue` (sum remains 3)- For `i = 6`: `6 % 3` is `False` -> `sum += 6` (sum becomes

sum = 0 for i in range(1,10): if(i%3): continue sum+=i print(sum)

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What is the output of the following code? sum= 0 for i in range(1, 10): if i % 3: continue sum += i 3 print(sum)

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Chapter1: Introduction

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