### What is the output of the following code snippet?```cppint arr[5] = { 1, 2, 3, 4, 5 };int* ptr = arr;ptr = ptr + 2;cout << *ptr << endl;```- ( ) There is no output due to a compilation error.- ( ) 1- ( ) 2- (x) 3### Explanation:This code snippet is performing pointer arithmetic and array indexing in C++. Here is a step-by-step explanation:1. **Array Declaration:** An integer array `arr` of size 5 is initialized with the values `{ 1, 2, 3, 4, 5 }`.2. **Pointer Initialization:** A pointer `ptr` is declared and initialized to point to the first element of the array `arr`.3. **Pointer Arithmetic:** The pointer is then incremented by 2, so `ptr` now points to the third element of the array.4. **Dereferencing Pointer:** The value at the pointer (third element of the array) is printed using `cout`, which outputs `3`.

The provided code snippet involves an array of integers and a pointer in C++. It initializes an…

Answered: What is the output of the following…

What is the output of the following code snippet? int arr[5] = { 1, 2, 3, 4, 5 }; int* ptr = arr; ptr ptr + 2; cout << *ptr << endl; There is no output due to a compilation error. 1 2 3

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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What does the following code output? tinclude void pointerUpd (double* upt); int main() { double* pp; double b[6] = { 1.01, 2.02, 3.03, 4.04, 5.05 }; PP = 6 (b[4]); double *dp = pp; dp++; std::cout <« *dp < std::endl; std::cout « *pPp « std::endl; pointerUpd (pp) ; std::cout « *dp « std::endl; std::cout <« *pp << std::endl; void pointerUpd (double* upt) { * (++upt) = 6.06; upt = new double; *upt = 1.01;
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