### Code Snippet Question**What is the output of the following code snippet?**```cppint arr[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };int* ptr = arr;ptr = ptr + 5;cout << *ptr << endl;```**Options:**- ☐ There is no output due to a compilation error.- ☐ 4- ☐ 5- ☐ 6**Explanation:**This code snippet demonstrates pointer arithmetic in C++. The pointer `ptr` is initially assigned to the address of the first element in the array `arr`. By adding 5 to `ptr`, the pointer moves to the address of the sixth element in the array (since arrays are zero-indexed). Therefore, the line `cout << *ptr << endl;` outputs the value of the sixth element, which is `6`.

The code initializes an array arr with values 1 to 10, creates a pointer ptr pointing to the first…

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What does the following code output? tinclude void pointerUpd (double* upt); int main() { double* pp; double b[6] = { 1.01, 2.02, 3.03, 4.04, 5.05 }; PP = 6 (b[4]); double *dp = pp; dp++; std::cout <« *dp < std::endl; std::cout « *pPp « std::endl; pointerUpd (pp) ; std::cout « *dp « std::endl; std::cout <« *pp << std::endl; void pointerUpd (double* upt) { * (++upt) = 6.06; upt = new double; *upt = 1.01;
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What is the output of the following code snippet? int arr [10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; int* ptr = arr; ptr + 5; ptr cout << *ptr << endl; - There is no output due to a compilation error. 4 5 6