What is the output of the following code:```cpp#include #include using namespace std;int main() { double x = 142.366; cout << setw(5) << setiosflags(ios::fixed) << setprecision(2) << x << endl; cin.ignore(); return 0;}```### Explanation:This C++ code sets a double variable `x` to `142.366`. The `cout` statement uses manipulators `setw(5)`, `setiosflags(ios::fixed)`, and `setprecision(2)`.- `setw(5)`: Sets the width of the output field to 5 characters. However, since `142.37` (after applying precision) requires more than 5 characters, this has no effect here.- `setiosflags(ios::fixed)`: Ensures the number is printed in fixed-point notation.- `setprecision(2)`: Sets the precision of the output to 2 decimal places.As a result, the output will be:```142.37```

Answered: What is the output of the following…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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What is the output of the following code: #include #include using namespace std; int main(){ double x = 142.366; cout <« setw( 5) << setiosflags(ios::fixed) << setprecision(2) << x « endl; cin.ignore(); return 0; }