What is the output of the following C++ code? explain each step. int alpha[8]; for (int i = 0; i < 4; i++) { alpha[i] = i * ( i + 1);    if (i % 2 == 0)       alpha[4 + i] = alpha[i] + i;   else if (i % 3 == 0)      alpha[4 + i] = alpha[i] - i;   else if (i > 0)      alpha[4 + i] = alpha[i] - alpha[i - 1]; } for (int i = 0; i < 8; i++) cout << alpha[i] << " "; cout << endl;

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
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What is the output of the following C++ code? explain each step.

int alpha[8];

for (int i = 0; i < 4; i++)

{ alpha[i] = i * ( i + 1);

   if (i % 2 == 0)

      alpha[4 + i] = alpha[i] + i;

  else if (i % 3 == 0)

     alpha[4 + i] = alpha[i] - i;

  else if (i > 0)

     alpha[4 + i] = alpha[i] - alpha[i - 1]; }

for (int i = 0; i < 8; i++)

cout << alpha[i] << " "; cout << endl;

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