What is the output of the following C++ code?double salary[5] = {35700, 96800, 55000, 72500, 87700};double raise =0.02;cout << fixed << showpoint << setprecision(2);for (int i = 0; i < 5; i++)cout << (i + 1) << " " << salary[i] << " "<< salary[i] * raise << endl;

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A: The correct option is option A

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A: x[4] is passed by reference x[2] is passed as value

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A: Actually, c++ is case sensitive, general purpose, free-form programming language.

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A: Decrement operator is the "--" operator.

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