What will the output be after the execution of this code? void changeToFive(int num1); int main() { int num = 1; cout << "In the main function, the number is: " << num << endl; changeToFive(num); cout << "Now the output is " << num << endl; return 0; } void changeToFive(int num1) { num1 = 5; cout << "The number is now: << num1 << endl; }
What will the output be after the execution of this code? void changeToFive(int num1); int main() { int num = 1; cout << "In the main function, the number is: " << num << endl; changeToFive(num); cout << "Now the output is " << num << endl; return 0; } void changeToFive(int num1) { num1 = 5; cout << "The number is now: << num1 << endl; }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:### Code Explanation
In this example, we have a C++ code snippet that involves a function call and outputs to the console. Let's break it down:
#### Code
```cpp
void changeToFive(int num1);
int main()
{
int num = 1;
cout << "In the main function, the number is: " << num << endl;
changeToFive(num);
cout << "Now the output is " << num << endl;
return 0;
}
void changeToFive(int num1)
{
num1 = 5;
cout << "The number is now: " << num1 << endl;
}
```
#### Analysis
1. **Main Function Execution:**
- The program begins by entering the `main()` function.
- An integer variable `num` is initialized with the value `1`.
- It prints: `"In the main function, the number is: 1"`
2. **Function Call `changeToFive(num)`:**
- The value of `num` (which is `1`) is passed to the `changeToFive` function.
- Inside `changeToFive`, the variable `num1` is a copy of `num`.
- The line `num1 = 5;` changes the local copy `num1` to `5`.
- It prints: `"The number is now: 5"`
- Note: This change does not affect `num` in the `main()` function.
3. **After the Function Call:**
- Control returns to `main()`.
- It prints: `"Now the output is 1"`
#### Conclusion
The output after executing this code will be:
```
In the main function, the number is: 1
The number is now: 5
Now the output is 1
```
This illustrates the concept of pass-by-value in C++, where modifications to function parameters do not affect the original arguments.
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