What is the order of growth of the worst-case running time of the get (i) function in SLList class?template ItemType &SLList: :get (int i) const {Node *p = sentinel->next;for (int j = o; i < i; j++) // until hitting the i-th itemp = p->next;return p->item;}O(log N)O(N)O(N log N)O(1)

Hey there, I am writing the required solution based on the above given question. Please do find the…

What is the order of growth of the worst-case running time of the get (1) function in SLList class? template ItemType sSLList::get (int i) const { Node *p = sentinel->next; for (int j = 0; j < i; j++) // until hitting the i-th item p - p->next; return p->item; O Olog N) O O(N) O O(N log N) O 0(1)

What is the order of growth of the worst-case running time of the get (1) function in SLList class? template ItemType sSLList::get (int i) const { Node *p = sentinel->next; for (int j = 0; j < i; j++) // until hitting the i-th item p - p->next; return p->item; O Olog N) O O(N) O O(N log N) O 0(1)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Simplify the following Boolean equations. Show your work and list which axiom or theorem you used in each step. Your final equation should be in minimized sum-of-products(SOP) form. Y = [AB' + (A'B+(CD)'+E)]' Please list each therom used line by line.
write the following usong for loops
Less'Implement an extractLessThan operation on a singly-linked list with no tail pointer. Your code SHOULD NOT delete memory, only return a new LinkedList with the value less than parameter value. Your code must not call other LinkedList functions. Order of the extracted nodes does not matter. 8. struct LinkNode { Data • data; // note that you can compare by calling data->compareTo(other) LinkNode • next; }; class LinkedList { LinkNode • head; • Returns a nev LinkedList that contains all of the LinkNodes from this • LinkedList that have node->data->compareTo (value) extractLessThan(value); • // x nov contains [5, 8] and y nov contains (3, 1 // You have access to head and to this LinkedList extractLessThan (Data • value) { LinkedList nevList - new LinkedList(); LinkNode • current - head; LinkNode • previous - NULL;
8. Implement an extractLessThan operation on a singly-linked list with no tail pointer. Your code SHOULD NOT delete memory, only return a new LinkedList with the value less than parameter value. Your code must not call other LinkedList functions. Order of the extracted nodes does not matter. struct LinkNode { Data • data; // note that you can compare by calling data->compareTo(other) LinkNode • next; class LinkedList { LinkNode • head; • Returns a nev LinkedList that contains all of the LinkNodes from this • LinkedList that have node->data->compareTo (value) extractLessThan (value); • // x nov contains [5, 8] and y now contains (3, 1] // You have access to head and to this LinkedList • extractLeseThan (Data • value) { LinkedList • nevList - nev LinkedListO: LinkNode • current - head; LinkNode • previous - NULL;
What statement is the most appropriate for the following f1 function? template <class Item> int f1(binary_tree_node<Item> node) { int answer = 0; if (node->left( )!= NULL) ++answer; if (node->right( )!= NULL) ++answer; eturn answer; } Group of answer choices The f1 function computes the number of left children that a node has. The f1 function computes the number of ancestors that a node has. The f1 function computes the number of leaves that a node has. The f1 function computes the number of children that a node has. The f1 function computes the number of right children that a node has.
Computer Science PLEASE HELP TO CONVERT THIS FOR LOOP TO FOREACH LOOP using System;using System.Collections.Generic; namespace SwinAdventure{public class IdentifierableObject{//field ,datapublic List<string> Identifier = new List<string>(); //constructorpublic IdentifierableObject(string[] ident){for (int i = 0; i < ident.Length; i++){Identifier.Add(ident[i]);}} // Methodpublic void AddIdentifier(string id){Identifier.Add(id.ToLower());} // propertiespublic string FirstID{get{return Identifier[0];}} public bool AreYou(string id){for (int i = 0; i < Identifier.Count; i++){if (Identifier[i] == id.ToLower()){return true;} }return false;}}}
what is the problem in the display function ? the code : #include <iostream>using namespace std; class node{public: int data; node* next;}; void display(node * head) // printing the data of the nodes{ node* temp = head; while (temp != NULL) { cout << temp->data << endl; temp = temp->next; }} // add void push(node** head, int newdata) // { 5, 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = *head; *head = newnode;} void append(node** head, int newdata) // { 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = NULL; node* last = *head; if (*head == NULL) { *head = newnode; return; } while (last->next != NULL) { last = last->next; } last->next = newnode;} void insertafter(node*…
Make an array of linked list for the following C code: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 = poly1->next;} // If power of…
my code needs help. please fix template <class T> class Node { public: /// CTORS Node() : prev_(nullptr), next_(nullptr) {} Node(T element) : element_(element), prev_(nullptr), next_(nullptr) {} Node(T element, Node *prev, Node *next) : element_(element), prev_(prev), next_(next) {} /// Set the pointer to the previous element void setPrevious(Node *prev) { prev_ = prev; } /// Set the pointer to the previous element void setPrev(Node *prev) { prev_ = prev; } /// Get a pointer to the previous element Node *getPrevious() { return prev_; } /// Get a pointer to the previous element Node *getPrev() { return prev_; } /// Set the pointer to the next node void setNext(Node *next) { next_ = next; } /// Get a pointer to the next node Node *getNext() { return next_; } /// Set the element this node holds void setElement(T element) { element_ = element; } /// Get the element this node holds T &getElement() { return element_; } /// Return a reference to the element T…
Parking (car Cars[], car Park[], int Area) { Car Cr, int CrNb; CrNb <-- 0; Park <-- { }; Cr <-- Select (Cars) I/ Cr = / if the Cars = {} while (Feasible (Cr)) do { Remove (Cr, Cars); Add (Cr, Park); CrNb <-- CrNb +1; Cr <-- Select (Cars) } if exist-Solution (Park) Then Success else return Error } Trace the above Greedy algorithm with the following data: Area = 1000, Cars [100, 50, 90, 70. 200, 300, 400, 80, 200] the cost for each parked car is 3JD. The objective function is: %3D k Max (ΣCis 1000) K |=1
The following procedure removes the first half of the list passed as a parameter: public static void foo( List myList) { int theSize = myList.size( ) / 2; for( int i = 0; i < theSize; i++ ) myList.remove( 0 ); } What is the running time of foo if myList is a LinkedList? e(1) O e(n Ig n) O(n) O e(n³) e(n?)
be fast please