What is the observed value of the test statistic for the appropriate hypothesis test? Give answer to 3 decimal places.

MATLAB: An Introduction with Applications
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What is the observed value of the test statistic for the appropriate hypothesis test? Give answer
to 3 decimal places.
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Transcribed Image Text:What is the observed value of the test statistic for the appropriate hypothesis test? Give answer to 3 decimal places. Answer:
Random samples of 110 homes in Kingston, Ontario (n₁) and 100 homes in Owen Sound,
Ontario (₂) were selected. Each home was examined for the presence of asbestos, and it was
found that 20 homes in Owen Sound and 35 homes in Kingston had some presence of
asbestos.
We would like to test whether the proportion of homes with asbestos in Kingston (P₁) is greater
than the proportion of homes in Owen Sound with asbestos (p₂). What test statistic should we
use? Here, we will denote by p the proportion of homes with asbestos in Kingston and Owen
Sound combined.
Select one:
4
O a. X² = Σ =1
4
X, where Ek is the expected number of observations, and
Ok is the actual number of observations, in the cells of the contingency table
corresponding to this problem.
~ N(0, 1)
O b. Z=
O c. Z =
(Ek-Ok)²
Ek
P₁-P₂
√(p(1-p)(1/n₁+1/m₂)
~
P1-P₂
√(pi(1-p₁/n+p2(1-p2)/m₂)
~ N(0, 1)
Transcribed Image Text:Random samples of 110 homes in Kingston, Ontario (n₁) and 100 homes in Owen Sound, Ontario (₂) were selected. Each home was examined for the presence of asbestos, and it was found that 20 homes in Owen Sound and 35 homes in Kingston had some presence of asbestos. We would like to test whether the proportion of homes with asbestos in Kingston (P₁) is greater than the proportion of homes in Owen Sound with asbestos (p₂). What test statistic should we use? Here, we will denote by p the proportion of homes with asbestos in Kingston and Owen Sound combined. Select one: 4 O a. X² = Σ =1 4 X, where Ek is the expected number of observations, and Ok is the actual number of observations, in the cells of the contingency table corresponding to this problem. ~ N(0, 1) O b. Z= O c. Z = (Ek-Ok)² Ek P₁-P₂ √(p(1-p)(1/n₁+1/m₂) ~ P1-P₂ √(pi(1-p₁/n+p2(1-p2)/m₂) ~ N(0, 1)
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