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What is the n'th order term in the Taylor series expansion of the function f (z) = exp z about z= -3 %3D (B) z+ 3)" n! e (z-3)"+1 (C) 2n+1 (n+1)! (A) (z+3)" n! e-3 (z+3)"-1 (D) 2m e-3 (z- 3)"-1 (E) 2n (n– 1)! n!

What is the n'th order term in the Taylor series expansion of the function f (z) = exp z about z= -3 %3D (B) z+ 3)" n! e (z-3)"+1 (C) 2n+1 (n+1)! (A) (z+3)" n! e-3 (z+3)"-1 (D) 2m e-3 (z- 3)"-1 (E) 2n (n– 1)! n!

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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What is the n'th order term in the Taylor series expansion of the function f (z) = exp z about z= -3 %3D (B) z+ 3)" n! e (z-3)"+1 (C) 2n+1 (n+1)! (A) (z+3)" n! e-3 (z+3)"-1 (D) 2m e-3 (z- 3)"-1 (E) 2n (n– 1)! n!
Transcribed Image Text:What is the n'th order term in the Taylor series expansion of the function f (z) = exp z about z= -3 %3D (B) z+ 3)" n! e (z-3)"+1 (C) 2n+1 (n+1)! (A) (z+3)" n! e-3 (z+3)"-1 (D) 2m e-3 (z- 3)"-1 (E) 2n (n– 1)! n!
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