What is the net torque on the object shows below rotating about the point labeled O? (Give counterclockwise) your answer in N m. The positive direction is r₁ = 2.69 m r₂ = 5.23 m 6.00 N Answer: 45.0° 15.0 N 4.00 N

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### Problem Statement

What is the net torque on the object shown below rotating about the point labeled O? (Give your answer in N·m. The positive direction is counterclockwise).

- \( r_1 = 2.69 \, \text{m} \)
- \( r_2 = 5.23 \, \text{m} \)

### Diagram Explanation

The diagram shows a circular object with a point \( O \) at its center. From this point, two radii are labeled: \( r_1 \) and \( r_2 \).

- **Force 1**: 6.00 N acting leftwards along the top of the circle.
- **Force 2**: 15.0 N acting at a 45-degree angle to a line extending horizontally from the center.
- **Force 3**: 4.00 N acting downwards on the right of the circle.

### Calculation Steps

To solve for the net torque, you need to consider the torque produced by each force about point \( O \). Torque (\( \tau \)) is calculated using the formula:

\[ \tau = r \cdot F \cdot \sin(\theta) \]

where:
- \( r \) is the radius,
- \( F \) is the force,
- \( \theta \) is the angle between the force and the lever arm.

Now calculate the torques:

1. **Torque due to the 6.00 N force** (Force 1):
   - \( \tau_1 = r_1 \times 6.00 \, \text{N} = 2.69 \, \text{m} \times 6.00 \, \text{N} \)
   - This force is perpendicular to \( r_1 \), so \(\sin(90^\circ) = 1\).

2. **Torque due to the 15.0 N force** (Force 2):
   - \( \tau_2 = r_2 \times 15.0 \, \text{N} \times \sin(45^\circ) = 5.23 \, \text{m} \times 15.0 \, \text{N} \times \sin(45^\circ) \)

3. **Torque due to the 4.00 N force** (Force 3):
   -
Transcribed Image Text:### Problem Statement What is the net torque on the object shown below rotating about the point labeled O? (Give your answer in N·m. The positive direction is counterclockwise). - \( r_1 = 2.69 \, \text{m} \) - \( r_2 = 5.23 \, \text{m} \) ### Diagram Explanation The diagram shows a circular object with a point \( O \) at its center. From this point, two radii are labeled: \( r_1 \) and \( r_2 \). - **Force 1**: 6.00 N acting leftwards along the top of the circle. - **Force 2**: 15.0 N acting at a 45-degree angle to a line extending horizontally from the center. - **Force 3**: 4.00 N acting downwards on the right of the circle. ### Calculation Steps To solve for the net torque, you need to consider the torque produced by each force about point \( O \). Torque (\( \tau \)) is calculated using the formula: \[ \tau = r \cdot F \cdot \sin(\theta) \] where: - \( r \) is the radius, - \( F \) is the force, - \( \theta \) is the angle between the force and the lever arm. Now calculate the torques: 1. **Torque due to the 6.00 N force** (Force 1): - \( \tau_1 = r_1 \times 6.00 \, \text{N} = 2.69 \, \text{m} \times 6.00 \, \text{N} \) - This force is perpendicular to \( r_1 \), so \(\sin(90^\circ) = 1\). 2. **Torque due to the 15.0 N force** (Force 2): - \( \tau_2 = r_2 \times 15.0 \, \text{N} \times \sin(45^\circ) = 5.23 \, \text{m} \times 15.0 \, \text{N} \times \sin(45^\circ) \) 3. **Torque due to the 4.00 N force** (Force 3): -
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