What is the most appropriate analysis given the results on testing of assumptions? Justify your answer
What is the most appropriate analysis given the results on testing of assumptions? Justify your answer
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
What is the most appropriate analysis given the results on testing of assumptions? Justify your answer
Transcribed Image Text:Problem: Mr. Kinalabaw, an owner of a mango plantation, is worried about the
increasing number of fruit piercing moths present in most of the mango trees in his
farm. He then asked for Concon's help, his trusted statistician, in resolving the
problem. They identified two types of pesticide (1, 2) and two methods of
application (A, B). They applied each treatment combination to 3 fruit piercing
moths. Their survival time (in minutes) was recorded.
Pesticide
Method of
Application
Survival Time (in minutes)
A
31
29
30
1
B
28
30
27
A
23
18
20
2
B
17
15
18
data: Pesticide 1 Method A data:
Pesticide 1 Method B
Shapiro-Wilk normality test
Shapiro-Wilk normality test
W 1.00000,
W 0.96429,
p-value 1.0000
p-value 0.6369
data: Pesticide 2 Method A data:
data: Pesticide 2 Method B
Shapiro-Wilk normality test Shapiro-Wilk normality test
W 0.98684
0.96429
p-value 0.7804
p-value 0.6369
Bartlett test of homogeneity of variances
data: survival time by trmcombin
Bartlett's K-squared 1.4136, df 3, p-value 0.7024
Levene's Test for Homogeneity of Variance (center "mean")
DE F value Pr (>F)
group 3 0.8718 0.4947
8
Anova Table (Type II testa)
Response: survival time
method
pesticide
Sum Sq Df value
Pr (>F)
21.33 1 7.1111 0.02851.
341.33 1 113.7778 0.000005232 ***
0.34659
methodipesticide 3.00 1 1.0000
Residuals
24.00 8
。
---
Signif. codes: 0 0.001 0.01 0.05 0.1
Kruskal-Wallis rank sum test
data: survival time by trmcombin
Kruskal-Wallis chi-squared 9.6573, df 3, p-value = 0.02172
Transcribed Image Text:Test
Conclusion
p-value
0.7024
Homogeneity of Variances
Since 0.7024 > 0.05 at = 5%, we
do not have enough evidence to
conclude that the variances are
not homogenous
Shapiro-Wilk Normality Test
p-value
Conclusion
1.0000
*TC1: Pesticide 1, Method
Application A
0.6369
*TC2: Pesticide 1, Method of
Application B
We can assume normality for all
the treatment combinations since
their p-value > 0.05 at 5%.
*TC3: Pesticide 2, Method of
0.7804
Application A
*TC4: Pesticide 2, Method of
0.6369
Application B
*TC - Treatment Combination
What is the most appropriate analysis given the results on testing of assumptions?
Justify your answer.
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