what is the moment amplification factor, B1, for the member shown in Problem 6.2-2?a. Use LRFDb. Use ASD 2 How much service live load, in kips per foot, can be supported? The memberweight is the only dead load. The axial compressive load consists of a ser-vice dead load of 10 kips and a service live load of 20 kips. Do not considermoment amplification. Bending is about the x axis, and the steel is A992.a. Use LRFD.b. Use ASD.20'–W18 X 86FIGURE P6.2-2

Euler’s Buckling Load can be calculated as; Pel= π2EI*(K1L)2 Where, EI*- is the reduced stiffness of the member . K1L- the effective length of member L - is the length of the member In the direct analysis method, EI* = 0.8τbEIx Substitute the values in above expression; Pel= π2EI*(K1L)2Pel= π20.8τbEIx(KxL)2 where, E - the elastic modulus of steel Ix - is the moment of inertia of section about major principal axis Kx - is the buckling factor about x-axis . L - is the length of member . Substitute 29000 ksi for E, 1750 in4 for Ix, 1.0 for τb, 1.0 for Kx, 20 ft × 12 in.1 ft for L. Pel= π2 × 0.8 × 2900 × 1750(1.0 × 20 × 12)2= 6956.7 kips Computing the moment factor Cm as follows: For a transversely loaded member, the value of Cmis taken to be 1.0. Member is transversely loaded Cm = 1.0 The moment amplification factor B1 is calculated as. (a) LRFD method: B1 =Cm1-αPuPel Where, the value of the constant α is 1.0 and Pr is the axial load on the member. Pr = Pu where, Pu is the factored load on member. factored load on the member is calculated as: Pu =1.2PD + 1.6PL where, PD is the axial dead load , PL is the axial live load. Substituting values in above expression Pu =1.2PD + 1.6PL= (1.2 × 10 + 1.6 × 20)=44.0 kips Moment amplification is calculated as; B1 =Cm1-αPuPel Substitute value in above expression B1 = 1.01-1.0×446956.7= 1.01 Therefore, the moment amplification factor is 1.01 (b) ASD method: B1 =Cm1-αPaPel Where, the value of the constant α is 1.6 and Pa is the allowable load on the member. Allowable load on the member is calculated by: Pa = PD+PL Substitute the values in above expression where 10 kips for PD and 20 kips for PL. Pa = PD+PL= 10+20=30 kips Moment amplification can be calculated as: B1 =Cm1-αPuPel Substitute the values in above expression where 1.0 for Cm, 30 kips for Pa, 1.60 for and 6956.7 kips for Pel. B1 =1.01-1.60×306956.7=1.01 Therefore, the moment amplification factor is1.01.

Answered: what is the moment amplification…

Engineering

Civil Engineering

what is the moment amplification factor, B1, for the member shown in Problem 6.2-2? a. Use LRFD b. Use ASD

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: I1-3x B ニ (x²+2x-3[x-2) メ- X+3 メー2

A: Given:-

Q: Determine the force in each member.

A: To find force in all members of the truss

Q: The cmposite beam is made of 6061-T6 aluminum (A) and C83400 red brass (B). The the height, h=40mm,…

A: Section Properties : For transformed section:

Q: Determine the moment of each of the three forces about point A. (MF1) A¹ (MF2) A¹ (MF3) A = -433…

Q: M and de te

A: Taking moment about A, For Moment diagram, the following table shows moments in various sections…

Q: Determine the Maximum Normal ste developed stress in the bar buth at the cim section Containing the…

A: Stress concentration for the fillet - wh = 5224 = 2.167andrh = 1424 = .5833Hence,K = 1.5 Maximum…

Q: For the plate shown, the distance d required to eliminate the flexural .effect at section a - a is…

A: True

Q: Determine the moment of the forces acting on the structure about point A. ´HIS IS AN EXAM. DO 90N…

A: In this question, Two forces of 90 KN and 20 KN are acting on the structure. 90 KN acts at 50 degree…

Q: CDEFGH is plate with a circular hole in it and has a unit weight p (N/m²). It is attached on DE beam…

A: Center of gravity: The point in a system where the total weight or mass of the body is assumed to be…

Q: Please can you you supply me with the shear force diagram for question 3

Q: = 57 kN acts on the structure at D. Assume L₁-780 mm., L₂-390 mm., a-690 mm., b=360 mm., and c=1 (a)…

Q: The pin-connected structure consists of a rigid bar ABCD and two axial members. Bar (1) is bronze [E…

A: Load P = 56 kNA1 = 600 mm2 and A2 = 300 mm2E1 = 110 GPa and E2 = 77 GPa

Q: Using both LRFD and ASD methods, and disregarding the moment amplifications, determine if the member…

Q: 5. [AB,0A] Use conjugate beam method. (EI is constant) 22 Mo B

Q: Refer to the Column Interaction Given: F’c = 27.5 Mpa Fy = 414 Column diameter 400mm Main bar…

A: Step 1: Refer to the interaction Diagram so you can find the pg. and use the formula for the Area…

Q: Find the reactions of the fixed end at B. NO

Q: EX:- Analyze by the ConSistent defor mation.method the beaum Shown and than Draw S-F D and B-MD EI…

A: DS=re-2=3-2=1above beam is indeterminate to first degree then considering reaction RB as…

Q: etermine the support reaction Rc, in the simply supported beam shown below. Your answer should be in…

A: Apply equilibrium condition : We apply given three equilibrium condition to solve the support…

Q: The switch shown is designed to close as the temperature rises causing AB and CD to expand and…

A: Coefficient of thermal expansion of steel (αs) = 12 x 10-6 /oC Coefficient of thermal expansion of…

Q: Replace the three forces which act on the bent har by a force - couple system at the support point A…

A: Consider the following diagram: Draw the free body diagram of the system as follows:

Q: A. Reactions A and B B. Force in members GH,FH,GF, and FE. Identify if T or C

Q: (2) jlibäi The bar ABCD is fixed at A by a pin and supported by two wires as shown in fig. the bar…

A: Given:- The bar ABCD is fixed at A The bar ABCD is supported by two wires i.e. steel and copper…

Q: Force Method of Analysis: Beams Example 1 Determine the reaction at the roller support B of the beam…

Q: 350 기 mm 2400mm 400mm C A B 200mm 8 notice not hinge E 3 D =1 200kg

A: To Determine Reactions at pin C and D on member CDE where E is a roller and A is a pin

Q: Solve for this please. Thank you!

A: As there are two questions posted, according to guidelines only the first is being answered. Kindly…

Q: Question 13 of 14 > - /5 View Policies Current Attempt in Progress Determine the coordinates of the…

Q: The rigid you beam is Supported by a pin at A d wires BD and CE. IP the load Pon the beam ause the…

A: A rigid beam is there which is supported by a Pin at A and a wire BD and CE. now a load P on the…

Q: P9-1 D The steel rod (E= 200GPA) is subjected to the loading shown. If the cross-sectional area of…

Q: 1. Hibbeler 9-2 For the beam shown El is constant a) Use flexibility (method of consistent…

A: Objective: solve the beam using flexibility method. Solution: In this case we need to find the basic…

Q: Current Atte The pin-connected structure consists of a rigid beam ABCD and two supporting bars. Bar…

Q: Determine the angle of twist of the end A of the A-36 steel shaft shown in Fig.a. Also, what is the…

Q: The pin-connected structure consists of a rigid bar ABCD and two axial members. Bar (1) is bronze [E…

Q: ethod of joints. State whether the forces are in tension or compres 2 kip A НЕ B mūnu с -16 ft- i D…

A: To find force in all members of the truss

Question

100%

what is the moment amplification factor, B1, for the member shown in Problem 6.2-2?

a. Use LRFD

b. Use ASD

2 How much service live load, in kips per foot, can be supported? The member
weight is the only dead load. The axial compressive load consists of a ser-
vice dead load of 10 kips and a service live load of 20 kips. Do not consider
moment amplification. Bending is about the x axis, and the steel is A992.
a. Use LRFD.
b. Use ASD.
20'–
W18 X 86
FIGURE P6.2-2

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

this is just my reviewer for the expert's preferences
Use the conjugate beam methods
Use slope-deflection method to compute the bending moments of element ends for the following structures: 7) Use slope -defle ction Ast 4 4 12 t- 2006 Pa I= 100x 16mm" E = 200 GPa %3D I= 100× 106 mm4 For this question also compute the deflection at Point B.
Use the subsne member to make a compieneanlyss of e comples uss shown 25kN d 3m 25KN 4 m e1.5 m 2 at 4 m = 8 m
(c) The rigid bar ABC is suspended from three wires of the same material. The cross- sectional area of the wire at B is equal to half of the cross-sectional area of the wires at A and C. Determine the tension in each wire caused by the load P shown. ----|--²--| A 9 DAB T L P Fig. Q1(c) PL Hint: S = note that ABC is a rigid bar. EA C
Engineering analysis Deflection of beam-column Second and higher order linear
Principle of superposition The beam is indeterminate to the first degree. Force in member BD is chosen as the redundant. This member is therefore sectioned to eliminate its capacity to sustain a force. 60 kN/m 3 m 1.8 m 60 45 actual structure (a) 160 kN/m B FaD redundant рrimary structure ARD FRp applied Fap D
Solve the grven DE: vidv/dx)-g. when x-xo, v=vo. O v2-vo2-gte-xD) O v2rvo2-gx-xo) O 12-vo2-2gx-xol • v2-vo2-2gbx-xo)
Why do you integrate y instead of A? And why it’s it between 2a-a rather than 2a-0
Find the reactive elements and end moment of the beam shown by double integration.
The rods of Fig. are frictionless. The coefficient of friction between the 40- kg slider block and the floor is 0.40. Determine are lightweight and all pins The angle 0 that gives the absolute greatest force P for which motion does not occur. 6 m 3 m Im 4 m