What is the molarity of ZnCl2 that forms when 30.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 265 mL . Zn(s)+CuCl2(aq)→ZnCl2(aq)+Cu(s)

Q: What volume, in L, of 0.394 M NiCl2 solution is required to produce 50.9 g of precipitate.…

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Q: How many moles of precipitate will be formed when 260.0 mL of 0.200 M NaBr is reacted with excess…

A: Given : Molarity of NaBr = 0.200 M              Volume of solution = 260 mL To find : moles of PbBr2…

Q: 0.7532 g of copper turnings (molar mass: 63.546 g∙mol–1) are reacted with excess nitric acid.…

A: Disclaimer: In order to obtain copper sulfate the acid used in excess should be sulfuric acid and…

Q: What is the molarity of ZnCl2 that forms when 25.0 g of zinc completely reacts with CuCl2 according…

A: Molarity is defined as number of mole of substance divide by volume of solution in liter

Q: What volume, in mL, of 0.364 M Li2CO3 solution is required to react with 53.9 mL of 0.307 M HNO3.…

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Q: How many moles of precipitate will be formed when 125.0 mL of 0.150 M LiBr is reacted with excess…

A: Consider the given balanced equation as; 2 LiBr aq + PbNO32 aq → PbBr2 s + 2 LiNO3 aq  Consider the…

Q: Determine the mass of precipitate, in grams, that forms when 55.3 mL of 0.0424 M Na2CO3 reacts with…

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Q: What is the molarity of ZnCl2 that forms when 20.0 g of zinc completely reacts with CuCl2 according…

A: Given : Mass of Zn reacting = 20.0 g And volume of final solution = 285 mL = 0.285 L…

Q: Calculate the volume (in mL) of 0.100 M CaCl₂ needed to produce 1.00 g of . There is an excess of…

A: Molarity of CaCl2 = 0.100 MMass of CaCO3 = 1.00 gMolar mass of CaCO3 = 100.09 g/mol

Q: What volume (in mL) of 0.350 M HCl would be required to completely react with 3.90 g of Al in the…

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Q: What volume (in mL) of 0.250 M HCl would be required to completely react with 4.10 g of Al in the…

A: It is well known that by knowing the concentration and number of moles of any substance required for…

Q: How many grams of PbBr2 will precipitate when excess CuBr2 solution is added to 42.0 mL of 0.592 M…

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Q: What mass of precipitate (in g) is formed when 250.0 mL of 0.110 M CdCl2 is mixed with excess KOH in…

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Q: How many grams of precipitate are formed when 250.0 mL of 0.110 M ZnCl₂ is mixed with excess KOH in…

A: Zn(OH)2 is the precipitate in this reaction.Molecular mass of Zn(OH)2  = 99.424 g/mol

Q: Calculate the volume (in mL) of 0.666 M Na3PO4 solution needed to completely react with 50.60 mL of…

A: Copper chloride reacts with sodium phosphate and also gives copper phosphate .

Q: What mass of precipitate (in g) is formed when 250.0 mL of 0.200 M CoCl₂ is mixed with excess KOH in…

A: The balanced equation is given as;   CoCl2(aq) + 2 KOH (aq)→Co(OH)2(s)+2KCl(aq) From the question,…

Q: What volume (in mL) of 0.300 M HCl would be required to completely react with 5.00 g of Al in the…

A: The number of moles of aluminium can be calculated as,

Q: How many moles of precipitate will be formed when 152.0 mL of 0.150 M LiBr is reacted with excess…

A: Molarity of LiBr (M) = Moles of LiBr (n) ÷ Volume of LiBr solution (V)  n = M × V n = 0.150 ×…

Q: What volume (in mL) of 0.300 M HCl would be required to completely react with 5.05 g of Al in the…

A: Calculate the number of moles of aluminum. The molar mass of aluminum is 27 gram per mole.

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 23.0 mL of…

A: Number of moles of substance=Concentration of substance x Volume of substanceFor…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 31.0 mL of…

A: ZnNO32+2 NaOH→ZnOH2 s+2 NaNO3 aqStength of ZnNO32=20.5x0.700 M1000=0.0143Stength of NaOH=310x0.700…

Q: What quantity in moles of precipitate will be formed when 176.0 mL of 0.200 M NaBr is reacted with…

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Q: How many moles of precipitate will be formed when 120.0 mL of 0.150 M LiBr is reacted with excess…

A: The chemical reaction between aqueous LiBr and Pb(NO3)2 produces a solid precipitate of insoluble…

Q: How many moles of precipitate will be formed when 70.2 mL of 0.150 M AgNO₃ is reacted with excess…

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Q: What volume (in mL) of 0.09024 M HNO3 is required to react completely with 0.2432 g of potassium…

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Q: What volume (in mL) of 0.300 M HCl would be required to completely react with 3.45 g of Al in the…

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Q: Milk of magnesia, an over-the-counter antacid liquid, is a suspension of magnesium hydroxide in…

A: Given, Mass of Mg(OH)2 = 1.13g. Volume of HCl = 226.2mL. Molarity of HCl = 0.1746M. The moles of…

Q: Calculate the volume (in mL) of 0.500 M NA3PO4 solution needed to completely react with 66.73 mL of…

A: Given balanced chemical reaction is: 2Na3PO4(aq) + 3CuCl2(aq) ----> Cu3(PO4)2(s) + 6NaCl(aq)…

Q: In the laboratory, a student adds 41.7 mL of water to 16.1 mL of a 0.581 M hydrobromic acid…

A: Given , (a) Volume of water added = 41.7 mL Initial volume of water = 16.1 mL Concentration of HBr =…

Q: How many moles of precipitate will be formed when 108.5 mL of 0.200 M NaBr is reacted with excess…

A: Given,Volume of NaBr = 108.5 mL = 0.1085 L       (1 mL =0.001 L)Molarity of NaBr = 0.200 M = 0.2…

Q: How many moles of precipitate will be formed when 107.9 mL of 0.150 M LİBR is reacted with excess…

A: Limiting reagent is the reagent which is consumed in the chemical reaction completely. It decides…

Q: What volume (in mL) of 0.300 M HCI would be required to completely react with 5.55 g of Al in the…

A: Given information,    Concentration of HCl is 0.300 M.    Mass of Al is 5.55 g.

Q: What volume (in mL) of 0.400 M HCl would be required to completely react with 3.70 g of Al in the…

A: Molar mass of Al = 26.98 g/mol. Mass of Al = 3.70 g. Number of moles of Al is calculated as follows:…

Q: How many moles of precipitate will be formed when 147.0 mL of 0.200 M NaBr is reacted with excess…

A: Since you have posted question with multiple sub-parts, we are entitled to answer the first 3 only.…

Q: How many grams of Zn are required to react with 447.7 mL of 0.202 M HCl? Zn (s) + 2 HCl (aq) →…

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Q: What volume, in L, of 0.209 M NiCl2 solution is required to produce 69.4 g of precipitate.…

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Q: ium hydroxide solution according to the equation   HC2H3O2+NaOH⟶H2O+NaC2H3O2   If you require…

A: The given data : The volume of NaOH = 34.58 mL The molariry of NaOH= 0.1036 M The volume of acetic…

Q: 3. What is the concentration of sodium chloride in the final solution if 28.24 mL of 0.129 M BaCl₂…

A: We have to calculate the concentration of NaCl in the final solution

Q: 3. If 24.2 g of zinc is combined with hydrochloric acid (HCI) determine the molar concentration of…

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Q: What is the mass in grams of precipitate formed when 250.0 mL of 0.100 M ZnCl₂ is mixed with excess…

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Q: What volume (in mL) of 0.300 M HCl would be required to completely react with 5.40 g of Al in the…

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