What is the minimum speed needed to clear the loop? Diameter is 15m.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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What is the minimum speed needed to clear the loop? Diameter is 15m. 

**Problem Statement:**

"Find the minimum speed needed to clear the loop. Diameter is 15."

**Diagram Explanation:**

The diagram illustrates a vertical loop with a circular shape. There is a horizontal line representing the ground or a track. A circle is drawn above this line, symbolizing the loop, and it is bisected by a vertical diameter line. The loop is labeled with a diameter of 15, which is essential for calculating the necessary speed to clear the loop. The problem involves determining the minimum speed at which an object must travel to move around the entire loop without losing contact. 

**Concepts Involved:**

This problem involves concepts from physics, particularly centripetal force and motion in a vertical circle. The objective is to find the minimum velocity at the top of the loop that ensures continuous contact, which ties into gravitational forces and kinematic equations.
Transcribed Image Text:**Problem Statement:** "Find the minimum speed needed to clear the loop. Diameter is 15." **Diagram Explanation:** The diagram illustrates a vertical loop with a circular shape. There is a horizontal line representing the ground or a track. A circle is drawn above this line, symbolizing the loop, and it is bisected by a vertical diameter line. The loop is labeled with a diameter of 15, which is essential for calculating the necessary speed to clear the loop. The problem involves determining the minimum speed at which an object must travel to move around the entire loop without losing contact. **Concepts Involved:** This problem involves concepts from physics, particularly centripetal force and motion in a vertical circle. The objective is to find the minimum velocity at the top of the loop that ensures continuous contact, which ties into gravitational forces and kinematic equations.
Expert Solution
Step 1

Radius = 15/2 = 7.5 m 

To complete the loop speed required at bottom 

V = √(5gR)

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