Countries with excellent wind energy sources decide on national projects for the development of wind energy. Ten percent of the land area will be devoted to 1.5 kW wind energy per person, roughly the amount of electricity used by one person in an industrialized country.  2 MW wind turbine with a rotor of 80 m diameter is placed in the average layout space of the figure. Depending on the wind conditions, the average output is 650 kW per turbine. Calculate the maximum density of a single sphere consistent with this business plan. Align geographic information with Germany, Spain, India and Denmark (they all have active wind power programs), and discuss the possibilities for achieving this goal in each of these countries.

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Countries with excellent wind energy sources decide on national projects for the development of wind energy. Ten percent of the land area will be devoted to 1.5 kW wind energy per person, roughly the amount of electricity used by one person in an industrialized country.  2 MW wind turbine with a rotor of 80 m diameter is placed in the average layout space of the figure. Depending on the wind conditions, the average output is 650 kW per turbine. Calculate the maximum density of a single sphere consistent with this business plan. Align geographic information with Germany, Spain, India and Denmark (they all have active wind power programs), and discuss the possibilities for achieving this goal in each of these countries.

T
2-4 rotor
K diameters
ㅗ
ㅗㅗㅗㅗ
ㅗㅗ
CHAPTER 10: 풍력에너지
8-12
rotor
diameters
1
Prevailing
wind
direction
림 10.18: 풍력 발전 지역에서의 풍력 터빈의 최적 위치 조건, 거리는 회전자 직경의 함수로 나타난다.
은 그것의 최적 출력에 도달할 수 없게 될 것이다. 그림 10.18은 풍력 발전 지
부터비이 치저 이치 ㅈ것을 보여준다.
Transcribed Image Text:T 2-4 rotor K diameters ㅗ ㅗㅗㅗㅗ ㅗㅗ CHAPTER 10: 풍력에너지 8-12 rotor diameters 1 Prevailing wind direction 림 10.18: 풍력 발전 지역에서의 풍력 터빈의 최적 위치 조건, 거리는 회전자 직경의 함수로 나타난다. 은 그것의 최적 출력에 도달할 수 없게 될 것이다. 그림 10.18은 풍력 발전 지 부터비이 치저 이치 ㅈ것을 보여준다.
Expert Solution
Step 1

Figure 10.18 (ideal) provides the average crosswind distance and wind turbine spacing.

As a function of rotor diameter, the distance between wind turbines in a wind farm is displayed.

Downwind wind turbines will be spaced 8 times the diameter of their rotors apart.

lavg=8d

Here, d is the diameter of the wind turbine.

Substitute 10 m for d.

lavg=8×10 m       =80 m

The average crosswind spacing will be 3 times the rotor diameter.

bavg,cross wind=3d

Here, d is the diameter of the wind turbine.

Substitute 80 m for d.

bavg,cross wind=3×80 m                        =240 m

Calculate the land area required.

Aland=lavgbavg,cross head

Here, Aland=lavgbavg,cross head is the average crosswind spacing and lavgthe average spacing of the wind turbines downwind.

Substitute 800 m for lavg and 240 m for bavg, cross head.

 

Aland=800 m×240 m         =192000 m2×1 km2106 m2         =0.192 km2

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