Answered: What is the maximum amount of grams of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What is the maximum amount of grams of aluminum oxide (MM = 101.96 g/mol) that could be made by the reaction of (5.10x10^2) g of Al (MM = 26.98 g/mol) and (1.1000x10^2) g of O₂ (MM = 32.00 g/mol)?

The balanced reaction is 4 Al + 3 O₂ → 2 Al₂O₃.

Expert Solution

Step 1

The given reaction is:

$4 Al (s) + 3 O_{2} (g) \overset{}{\to} 2 {Al}_{2} O_{3} (s)$

$\begin{array}{rcl} The given mass of Al & = & 5.10 \times 10^{2} \\ Molar mass of Al & = & 26.98 g / mol \\ Number of moles of Al given & = & \frac{given mass}{molar mass} = \frac{5.10 \times 10^{2} g}{26.98 g / mol} = 18.90 mol \\ The given mass of O_{2} & = & 1.10 \times 10^{2} g \\ Molar mass of O_{2} & = & 32.0 g / mol \\ Number of moles of O_{2} given & = & \frac{given mass}{molar mass} = \frac{1.10 \times 10^{2} g}{32.0 g / mol} = 3.44 mol \end{array}$

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