< Question 15 of 25 > What is the mass m of an object that is attached to a spring with a force constant of 125 N/m if 22 complete oscillations occur each 13 s? kg m =

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### Question 15 of 25

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**Problem Statement:**

What is the mass \( m \) of an object that is attached to a spring with a force constant of 125 N/m if 22 complete oscillations occur each 13 s?

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**Answer:**

\[ m = \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \]

*kg*

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**Explanation:**

To find the mass \( m \) of the object, given the force constant \( k \) of the spring and the oscillation information, we can use the formula for the period \( T \) of a simple harmonic oscillator:

\[ T = 2\pi \sqrt{\frac{m}{k}} \]

First, we need to calculate the period \( T \). Given that there are 22 complete oscillations in 13 seconds, we find:

\[ T = \frac{13 \, \text{s}}{22} \]

Next, we can solve for \( m \) by rearranging the formula:

\[ m = \frac{T^2 \cdot k}{4\pi^2} \]

By substituting the given values, we can determine the mass \( m \). 

1. Calculate the period \( T \):
   \[ T = \frac{13}{22} \, \text{s} \]
   
2. Substitute \( T \) and \( k \) into the rearranged formula:
   \[ m = \frac{\left(\frac{13}{22}\right)^2 \cdot 125}{4\pi^2} \]

Finally, simplify the expression to find the mass \( m \).
Transcribed Image Text:### Question 15 of 25 --- **Problem Statement:** What is the mass \( m \) of an object that is attached to a spring with a force constant of 125 N/m if 22 complete oscillations occur each 13 s? --- **Answer:** \[ m = \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \] *kg* --- **Explanation:** To find the mass \( m \) of the object, given the force constant \( k \) of the spring and the oscillation information, we can use the formula for the period \( T \) of a simple harmonic oscillator: \[ T = 2\pi \sqrt{\frac{m}{k}} \] First, we need to calculate the period \( T \). Given that there are 22 complete oscillations in 13 seconds, we find: \[ T = \frac{13 \, \text{s}}{22} \] Next, we can solve for \( m \) by rearranging the formula: \[ m = \frac{T^2 \cdot k}{4\pi^2} \] By substituting the given values, we can determine the mass \( m \). 1. Calculate the period \( T \): \[ T = \frac{13}{22} \, \text{s} \] 2. Substitute \( T \) and \( k \) into the rearranged formula: \[ m = \frac{\left(\frac{13}{22}\right)^2 \cdot 125}{4\pi^2} \] Finally, simplify the expression to find the mass \( m \).
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