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What is the mass in grams of KBr in 0.400 L of a 0.350 M solution?

What is the mass in grams of KBr in 0.400 L of a 0.350 M solution?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please set up the answer the correct way. I am having a hard time with putting the units in the correct spots. 

### Calculation of Mass in Grams of KBr for a Given Solution #### Problem Statement: What is the mass in **grams of KBr** in **0.400 L** of a **0.350 M** solution? #### Input Section: - **Starting Amount**: Input fields to enter the initial values. The left input field is for the initial volume in liters (L), and the right input field is for the initial molarity (M). #### Calculation Section: - **Add Factor**: Buttons to add factors to the calculation. For example, multiplication (x) and parentheses ( ). - **Predefined Values**: - 8.43 × 10²² - 39.10 - 9.60 × 10^(-3) - 5.47 - 0.350 (the molarity of the KBr solution) - 0.140 - 7.09 × 10²⁰ - 16.7 - 1 - 136 (presumably the molar mass of KBr) - 0.400 (the volume in liters) - 1.18 × 10^(-3) - 6.022 × 10²³ (Avogadro's number) - 119 - **Units**: - g KBr (grams of KBr) - mol KBr (moles of KBr) - L (liters) - M KBr (molarity of KBr) - g KBr/mol (grams per mole of KBr) - mL (milliliters) #### Output and Reset Section: - **ANSWER**: Box to show the calculated answer. - **RESET**: Button to reset the calculation. ### Example Calculation Steps: 1. **Calculate Moles of KBr**: - Use the formula \( \text{Moles} = \text{Molarity} \times \text{Volume} \) - Here, \( \text{Moles} = 0.350 \, M \times 0.400 \, L \) - \( \text{Moles} = 0.140 \, \text{mol KBr} \) 2. **Convert Moles to Grams**: - Use the molar mass of KBr
Transcribed Image Text:### Calculation of Mass in Grams of KBr for a Given Solution #### Problem Statement: What is the mass in **grams of KBr** in **0.400 L** of a **0.350 M** solution? #### Input Section: - **Starting Amount**: Input fields to enter the initial values. The left input field is for the initial volume in liters (L), and the right input field is for the initial molarity (M). #### Calculation Section: - **Add Factor**: Buttons to add factors to the calculation. For example, multiplication (x) and parentheses ( ). - **Predefined Values**: - 8.43 × 10²² - 39.10 - 9.60 × 10^(-3) - 5.47 - 0.350 (the molarity of the KBr solution) - 0.140 - 7.09 × 10²⁰ - 16.7 - 1 - 136 (presumably the molar mass of KBr) - 0.400 (the volume in liters) - 1.18 × 10^(-3) - 6.022 × 10²³ (Avogadro's number) - 119 - **Units**: - g KBr (grams of KBr) - mol KBr (moles of KBr) - L (liters) - M KBr (molarity of KBr) - g KBr/mol (grams per mole of KBr) - mL (milliliters) #### Output and Reset Section: - **ANSWER**: Box to show the calculated answer. - **RESET**: Button to reset the calculation. ### Example Calculation Steps: 1. **Calculate Moles of KBr**: - Use the formula \( \text{Moles} = \text{Molarity} \times \text{Volume} \) - Here, \( \text{Moles} = 0.350 \, M \times 0.400 \, L \) - \( \text{Moles} = 0.140 \, \text{mol KBr} \) 2. **Convert Moles to Grams**: - Use the molar mass of KBr
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