**Title: Understanding Reaction Mechanisms with Deuterium****Question:**What is the major product of the shown reaction?**Reaction Details:**The reaction involves a phenylacetylene molecule \((C_6H_5C \equiv CH)\), which undergoes a reaction with \(1.) \, BD_3\) and \(2.) \, D_2O_2\).**Options for Major Product:**- **A:** Contains phenyl group with a hydroxyl (OH) and deuterium (D) atoms arranged.- **B:** Contains phenyl group with all deuterium (D) atoms.- **C:** Contains phenyl group with ketone and deuterium (D) atoms.- **D:** Contains phenyl group with both H and deuterium (D) present.- **E:** Contains phenyl group with ketone and deuterium atoms fully substituted.**Note:**Deuterium (chemical symbol - D) is a heavy isotope of hydrogen.- 1: Option A- 2: Option C- 3: This reaction won’t proceed as shown- 4: Option D- 5: Option BThis educational content helps in understanding isomerization and the role of isotopic labeling in reactions, crucial for tracing reaction mechanisms and predicting product formation.

Hydroboration–oxidation reaction: The hydroboration–oxidation reaction is a stereospecific two-step hydration reaction that converts an alkene into a carbonyl compound. This reaction results in the syn addition of hydrogen and a hydroxyl group at the double bond of an alkyne. This reaction is an anti-Markovnikov reaction, with the hydroxyl group attaching to the less-substituted carbon.The reaction proceeds in two steps. In the first step the enol is formed which is tautomerized into keto form in the second step. The reaction is given below:The right option is : B B.