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What is the half-life for the first-order decay of phosphorus-32? (3215P⟶3216S + e−)   The rate constant for the decay is 4.85 × 10−2 day−1.

What is the half-life for the first-order decay of phosphorus-32? (3215P⟶3216S + e−)   The rate constant for the decay is 4.85 × 10−2 day−1.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the half-life for the first-order decay of phosphorus-32? (3215P⟶3216S + e−)

  The rate constant for the decay is 4.85 × 10−2 day−1.

 

rate law units of rate constant integrated rate law Summary of Rate Laws for Zero-, First-, and Second-Order Reactions plot needed for linear fit of rate data relationship between slope of linear plot and rate constant half-life Zero-Order rate = k Ms1 [A] = -kt + [A]o [A] vs. t k = -slope t1/2 [A]o 2k First-Order rate = k[A] S-1 In[A] = -kt + In[A]o In[A] vs. t k = -slope t1/2 = 0.693 k Second-Order rate = K[A]² M1 S-1 [A] [A] vs. t = kt + k = slope t1/2 - (A.) 1 [A]ok
Transcribed Image Text:rate law units of rate constant integrated rate law Summary of Rate Laws for Zero-, First-, and Second-Order Reactions plot needed for linear fit of rate data relationship between slope of linear plot and rate constant half-life Zero-Order rate = k Ms1 [A] = -kt + [A]o [A] vs. t k = -slope t1/2 [A]o 2k First-Order rate = k[A] S-1 In[A] = -kt + In[A]o In[A] vs. t k = -slope t1/2 = 0.693 k Second-Order rate = K[A]² M1 S-1 [A] [A] vs. t = kt + k = slope t1/2 - (A.) 1 [A]ok
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