1. The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g) -> 4 NO2(g) + O2(g) at 70°C is 6.82 x 10³ s'. Suppose we start with 0.0250 moles of N2O5(g) in a volume of 2.0L. a) How many moles of N2O; will remain after 5.0 min? b) How many minutes will it take for the quantity of N2O5 to drop to 0.010 moles? c) What is the half-life of N,O5 at 70°C

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1.
The first order rate constant for the decomposition of N205, according to the reaction:
2 N2O5(g)
->
4 NO2(g) + O2(g)
at 70°C is 6.82 x 10³ s'.
Suppose we start with 0.0250 moles of N,O5(g) in a volume of 2.0L.
particle
a) How many moles of N2O, will remain after 5.0 min?
b) How
c) What is the half-life of N,O5 at 70°C
many
minutes will it take for the quantity of N2O5 to drop to 0.010 moles?
Transcribed Image Text:1. The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g) -> 4 NO2(g) + O2(g) at 70°C is 6.82 x 10³ s'. Suppose we start with 0.0250 moles of N,O5(g) in a volume of 2.0L. particle a) How many moles of N2O, will remain after 5.0 min? b) How c) What is the half-life of N,O5 at 70°C many minutes will it take for the quantity of N2O5 to drop to 0.010 moles?
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