1. The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g) -> 4 NO2(g) + O2(g) at 70°C is 6.82 x 10³ s'. Suppose we start with 0.0250 moles of N2O5(g) in a volume of 2.0L. a) How many moles of N2O5 will remain after 5.0 min? b) How many minutes will it take for the quantity of N2O5 to drop to 0.010 moles? c) What is the half-life of N2O5 at 70°C
1. The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g) -> 4 NO2(g) + O2(g) at 70°C is 6.82 x 10³ s'. Suppose we start with 0.0250 moles of N2O5(g) in a volume of 2.0L. a) How many moles of N2O5 will remain after 5.0 min? b) How many minutes will it take for the quantity of N2O5 to drop to 0.010 moles? c) What is the half-life of N2O5 at 70°C
Chemistry
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Chapter1: Chemical Foundations
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The first order rate constant for the decomposition of N205, according to the reaction:
2 N2O5(g)
4 NO2(g) + O2(g)
at 70°C is 6.82 x 10³ s'.
Suppose we start with 0.0250 moles of N2Os(g) in a volume of 2.0L.
a) How many moles of N,Os will remain after 5.0 min?
b) How many minutes will it take for the quantity of N,O5 to drop to 0.010 moles?
c) What is the half-life of N2O5 at 70°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe362d5a9-bcf1-4bcc-9808-2899b06de487%2F8c22b2ec-ddd1-4aee-907e-3f58fc8438bc%2Fsw9ixx_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1.
The first order rate constant for the decomposition of N205, according to the reaction:
2 N2O5(g)
4 NO2(g) + O2(g)
at 70°C is 6.82 x 10³ s'.
Suppose we start with 0.0250 moles of N2Os(g) in a volume of 2.0L.
a) How many moles of N,Os will remain after 5.0 min?
b) How many minutes will it take for the quantity of N,O5 to drop to 0.010 moles?
c) What is the half-life of N2O5 at 70°C
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