What is the expected value (mean) of X?

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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**Probability Distribution and Expected Value**

Consider a random variable with the following probability distribution:

| X | P(X) |
|---|------|
| 0 | 0.25 |
| 1 | 0.5  |
| 2 | 0.25 |

**Question: What is the expected value (mean) of X?**

Choices:
- O 1.0
- O 2.0
- O 0
- O Can't be determined

To determine the expected value (mean) of a discrete random variable X, we use the following formula:

\[ E(X) = \sum [X \cdot P(X)] \]

Let's calculate:

\[ E(X) = (0 \cdot 0.25) + (1 \cdot 0.5) + (2 \cdot 0.25) \]
\[ E(X) = 0 + 0.5 + 0.5 \]
\[ E(X) = 1.0 \]

Thus, the expected value (mean) of X is 1.0. The correct answer is:
- O 1.0
Transcribed Image Text:**Probability Distribution and Expected Value** Consider a random variable with the following probability distribution: | X | P(X) | |---|------| | 0 | 0.25 | | 1 | 0.5 | | 2 | 0.25 | **Question: What is the expected value (mean) of X?** Choices: - O 1.0 - O 2.0 - O 0 - O Can't be determined To determine the expected value (mean) of a discrete random variable X, we use the following formula: \[ E(X) = \sum [X \cdot P(X)] \] Let's calculate: \[ E(X) = (0 \cdot 0.25) + (1 \cdot 0.5) + (2 \cdot 0.25) \] \[ E(X) = 0 + 0.5 + 0.5 \] \[ E(X) = 1.0 \] Thus, the expected value (mean) of X is 1.0. The correct answer is: - O 1.0
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