What is the escape speed of a satellite located at the Moon's orbit about Earth? Assume the Moon is not nearby.
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A: a) Write the equation of Kepler’s third law.
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- Q A 'treetop satellite' moves in a circular orbit just above the surface of a planet, assumed to offer no air resistance. Show that its orbital speed v and the escape speed from the planet are related by the expression: ves = Sqrt(2)*v %3D(a) What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 182 km? m/s (b) What is the period of revolution? minThe acceleration of gravity is 9 m/s² at the surface of a planet of radius R=10°m. A satellite is to be launched from this planet into a circular orbit of radius 4R. (Probs. 8&9) 8. Find a value for the speed of this satellite when it is in this orbit. 9. Find the value of the initial velocity vo at which this satellite must be launched from the surface of the planet so that it reaches this orbit.
- A satellite moves in a circular orbit around Earth at a speed of 4381 m/s. (a) Determine the satellite's altitude above the surface of Earth. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m (b) Determine the period of the satellite's orbit. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. h Need Help? Read It6. (10 pts) Two satellites A and B are launched into Earth orbit. Satellite A has an orbit at an altitude of 200km. Satellite B has an orbit at an altitude of 400km. The radius of the Earth is 6370km. (a) What is the ratio of the potential energy of satellite B to that of satellite A? (b) What is the ratio of the kinetic energy of satellite B to that of satellite A (c) Which satellite has the greater total energy if each has a mass of 100 kg? (d) By how much?A satellite of mass 390 kg is in a circular orbit around the Earth at an altitude equal to the Earth's mean radius. Find the satellite's orbital speed.