What is the entropy change when 1.20 moles of CCl₂F2 condenses at 25.0 °C? [AH(vap) = 17.2 kJ/mol at 25.0 °C]

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What is the entropy change when 1.20 moles of CCl₂F2 condenses at
25.0 °C? [AH(vap) = 17.2 kJ/mol at 25.0 °C]
Transcribed Image Text:What is the entropy change when 1.20 moles of CCl₂F2 condenses at 25.0 °C? [AH(vap) = 17.2 kJ/mol at 25.0 °C]
Expert Solution
Step 1: Given information:

The temperature at which CCl2F2 condenses is given as 25.0 space to the power of o C.

The relationship between temperature in degrees Celsius and temperature in Kelvin is given by an expression:

T space left parenthesis K right parenthesis space equals space t to the power of space o end exponent C space plus space 273.15

Converting the given temperature in kelvin.

T space left parenthesis K right parenthesis space equals space 25.0 to the power of o C space plus space 273.15
space space space space space space space space space space equals space 298.15 space K space

The number of moles of CCl2F2 condensed is given as 1.20 space m o l e s.

The enthalpy of vaporisation, increment H subscript v a p end subscript is given as 17.2 space k J divided by m o l.

The relationship between kJ and J is given by an expression:

1 space k J space equals space 1000 space J

Converting increment H subscript v a p end subscript in J/mol.

increment H subscript v a p end subscript space left parenthesis i n space J divided by m o l right parenthesis space equals space open parentheses fraction numerator 1000 space J over denominator 1 space k J end fraction close parentheses space cross times space 17.2 space k J divided by m o l
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 17200 space J divided by m o l

We have to calculate the entropy change, increment S.

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