What is the enthalpy for reaction 1 reversed? reaction 1 reversed: 2NO + O2→2NO2

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What is the enthalpy for reaction 1 reversed?
reaction 1 reversed: 2NO + 02→2NO2
Express your answer numerically in kilojoules per mole.
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Hνα ΑΣφ
?
kJ/mol
ΔΗ-
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Part C Complete previous part(s)
Transcribed Image Text:What is the enthalpy for reaction 1 reversed? reaction 1 reversed: 2NO + 02→2NO2 Express your answer numerically in kilojoules per mole. • View Available Hint(s) Hνα ΑΣφ ? kJ/mol ΔΗ- Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Part C Complete previous part(s)
Learning Goal:
The change in enthalpy, AH, is the heat absorbed or produced during
any reaction at constant pressure. Hess's law states that AH for an
overall reaction is the sum of the AH values for the individual
reactions. For example, if we wanted to know the enthalpy change for
the reaction
3Mn + 302 3MnO2
we could calculate it using the enthalpy values for the following
individual steps:
Step 1: 4Al+ 302 2Al2O3
Step 2: 3Mn +2Al,O3 3MnO2 + 4Al
Overall: 3Mn + 302 3MnO2
If the enthalpy change is -3352 kJ/mol for step 1 and
1792 kJ/mol for step 2, then the enthalpy change for the overall
reaction is calculated as follows:
AH =-3352+1792 =-1560 kJ/mol
It is also important to note that the change in enthalpy is a state
function, meaning it is independent of path. In other words, the sum of
the AH values for any set of reactions that produce the desired
product from the starting materials gives the same overall AH
Par
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Transcribed Image Text:Learning Goal: The change in enthalpy, AH, is the heat absorbed or produced during any reaction at constant pressure. Hess's law states that AH for an overall reaction is the sum of the AH values for the individual reactions. For example, if we wanted to know the enthalpy change for the reaction 3Mn + 302 3MnO2 we could calculate it using the enthalpy values for the following individual steps: Step 1: 4Al+ 302 2Al2O3 Step 2: 3Mn +2Al,O3 3MnO2 + 4Al Overall: 3Mn + 302 3MnO2 If the enthalpy change is -3352 kJ/mol for step 1 and 1792 kJ/mol for step 2, then the enthalpy change for the overall reaction is calculated as follows: AH =-3352+1792 =-1560 kJ/mol It is also important to note that the change in enthalpy is a state function, meaning it is independent of path. In other words, the sum of the AH values for any set of reactions that produce the desired product from the starting materials gives the same overall AH Par Provi Type here to search
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