N204– 2NO2 (colorless) (reddish-brown) 0° C 25° C 100° C Ice Water Room Temperature Hot Water -As the temperature increased, what happened to the [N2O4]? -Was the formation of reactants or products favored by the addition of heat? -Which reaction is exothermic? -If the change of enthalpy of this reaction when proceeding left to right is 14 kcal, which chemical equation is correct? N204= 2NO2+ 14 kcal N204– 2NO2, HR = +14 kcal N204 + 14 kcal = 2NO2 N2O4– 2NO2, HR = -14 kcal

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Chapter1: Chemical Foundations
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Using this reversible reaction, answer the following:
N204= 2NO2
(colorless) (reddish-brown)
0° C
25° C
100° C
Ice Water
Room
Temperature
Hot Water
-As the temperature increased, what happened to the [N204]?
-Was the formation of reactants or products favored by the addition of heat?
-Which reaction is exothermic?
-If the change of enthalpy of this reaction when proceeding left to right is 14 kcal, which chemical equation is correct?
N204= 2NO2 + 14 kcal
N204= 2NO2, HR = +14 kcal
N204 + 14 kcal =
2NO2
N204= 2NO2, HR = -14 kcal
Transcribed Image Text:Using this reversible reaction, answer the following: N204= 2NO2 (colorless) (reddish-brown) 0° C 25° C 100° C Ice Water Room Temperature Hot Water -As the temperature increased, what happened to the [N204]? -Was the formation of reactants or products favored by the addition of heat? -Which reaction is exothermic? -If the change of enthalpy of this reaction when proceeding left to right is 14 kcal, which chemical equation is correct? N204= 2NO2 + 14 kcal N204= 2NO2, HR = +14 kcal N204 + 14 kcal = 2NO2 N204= 2NO2, HR = -14 kcal
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