Please help F2What is the energy of a mole of photons that have a wavelength of 605nm?@SWYour submission:3.28 x 10-19 J#3edCC$44VIncorrect, 2 attempts remaining%5tgbOllA6yhFeedback:It looks like your answer is off by a factor ofAvogadro's number (6.022 X 1023). Check the mathyou used to arrive to your answer and try again.hp&7OUj*8Oim(9kO<P)01PPР>;¡{Apr 2340+[?44*3:57 Obackspac1

Wavelength of the photon = 605 nm Using the data we have to calculate the energy of a mole of…

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Chemistry

What is the energy of a mole of photons that have a wavelength of 605 nm?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Quantum Chemistry

Quantum chemistry deals with the properties of chemical systems and their reactions. The branch of chemistry which is more concerned with quantum chemistry is physical chemistry. It is a more sophisticated field of theoretical physics which is concerned towards the application of physical concepts towards various chemical aspects such as, formation of atoms, chemical structure descriptions, chemical bond strength, hybridization, conjugation etc. Quantum chemistry mainly studies the various states i.e., ground state, excited state, transition states of the individual atoms or molecules taking place during any chemical reaction. The laws of motion explained by various scientists, which are termed as “classical mechanics” were not acceptable in terms of electrons, protons, atoms, light etc. Thus, a new theory named “quantum mechanics” emerged to understand the basic framework of various atomic and subatomic particles.

Question

Please help

F
2
What is the energy of a mole of photons that have a wavelength of 605
nm?
@
S
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Your submission:
3.28 x 10-19 J
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Incorrect, 2 attempts remaining
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you used to arrive to your answer and try again.
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