What is the energy in k.J/mole of photons associated with red light of wavelength 6.35 × 102 nm? Show your work for full credit.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Educational Content: Calculating Energy of Photons

#### Question:
What is the energy in kJ/mole of photons associated with red light of wavelength \(6.35 \times 10^2\) nm? *Show your work for full credit.*

#### Explanation:
To solve this problem, you need to follow these steps using the formulae related to photon energy:

1. **Convert Wavelength to Meters:**
   The given wavelength is \(6.35 \times 10^2\) nm, which is \(6.35 \times 10^{-7}\) meters (as \(1 \, \text{nm} = 10^{-9} \, \text{m}\)).

2. **Use the Energy Formula:**
   The energy of a photon can be calculated using the formula:
   \[
   E = \frac{hc}{\lambda}
   \]
   Where:
   - \(E\) is the energy of the photon in Joules (J)
   - \(h\) is Planck’s constant, \(6.626 \times 10^{-34}\) J·s
   - \(c\) is the speed of light, \(3.00 \times 10^8\) m/s
   - \(\lambda\) is the wavelength in meters

3. **Calculate Energy per Photon:**
   Substitute the values into the formula to calculate the energy per photon.

4. **Convert to Energy per Mole:**
   Since 1 mole of photons contains Avogadro's number (\(6.022 \times 10^{23}\) mol\(^{-1}\)), multiply the energy of one photon by Avogadro's number to obtain the energy in Joules per mole.

5. **Convert Joules to Kilojoules:**
   Convert the energy from Joules to kilojoules by dividing by 1000.

Once you have calculated these steps, you will find the energy in kJ/mole for the red light photons given. Remember to present your work clearly for full credit.
Transcribed Image Text:### Educational Content: Calculating Energy of Photons #### Question: What is the energy in kJ/mole of photons associated with red light of wavelength \(6.35 \times 10^2\) nm? *Show your work for full credit.* #### Explanation: To solve this problem, you need to follow these steps using the formulae related to photon energy: 1. **Convert Wavelength to Meters:** The given wavelength is \(6.35 \times 10^2\) nm, which is \(6.35 \times 10^{-7}\) meters (as \(1 \, \text{nm} = 10^{-9} \, \text{m}\)). 2. **Use the Energy Formula:** The energy of a photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] Where: - \(E\) is the energy of the photon in Joules (J) - \(h\) is Planck’s constant, \(6.626 \times 10^{-34}\) J·s - \(c\) is the speed of light, \(3.00 \times 10^8\) m/s - \(\lambda\) is the wavelength in meters 3. **Calculate Energy per Photon:** Substitute the values into the formula to calculate the energy per photon. 4. **Convert to Energy per Mole:** Since 1 mole of photons contains Avogadro's number (\(6.022 \times 10^{23}\) mol\(^{-1}\)), multiply the energy of one photon by Avogadro's number to obtain the energy in Joules per mole. 5. **Convert Joules to Kilojoules:** Convert the energy from Joules to kilojoules by dividing by 1000. Once you have calculated these steps, you will find the energy in kJ/mole for the red light photons given. Remember to present your work clearly for full credit.
Expert Solution
Step 1

The energy of the photon that associated with the red light is;

1nm=1×10-9 mE=hcλ=6.626×10-34 Js×3.0×108 m/s6.35×102 nm×10-9 m/nm=3.13×10-19 J

 

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