What is the empirical formula of C6H10O2?

Q: How many grams are in 3.01 × 1024 molecules of (NH4)2SO4?

A: Given,Molecules of NH42SO4 = 3.01 × 1024Required,                   Grams of NH4SO4 .

Q: The chemical formula for feldspar is K₂Al₂Si₆O₁₆. How many moles of feldspar are in 669.9 grams?

A: Number of moles of a substance is equal to the mass of substance divided by its molar mass. Write…

Q: What is the mass, in grams, of 9.29×1024 molecules of methanol (CH3OH

A: Given :-9.29x1024 molecules of methanolFirst convert molecules into moles9.29x1024molecules of…

Q: 5.000 gram sample of hydrated beryllium carbonate, BeCO3·xH2O is heated according to the procedure…

A: To calculate the number of moles of H2O and BeCO3.

Q: When 4.673 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.05 grams…

A: Given: Mass of compound burned = 4.673 g. Mass of CO2 produced = 16.05 g. Mass of H2O produced =…

Q: How many moles are in 3.45 x 10^23 molecules of H2CO3?

A:

Q: A molecule has an empirical formula of Ch2. 1.34 moles of the compound give 530.76 g of CO2 upon…

A: Given : We have to calculate the molecular formula.

Q: The chemical formula for chlorophyll is C₅₅H₇₂MgN₄O₅. Given the molar mass of the compound is 893.49…

A: Given, mass of C₅₅H₇₂MgN₄O₅. = 1.501 g Molar mass of C₅₅H₇₂MgN₄O₅. = 893.49 g/mol  Number of moles =…

Q: moles

A:

Q: How many moles of H₂O can be formed from 8.63 × 10²³ molecules of NH₃ from the following equation? 4…

A: Given:  Number of molecules of NH3 = 8.63 x 1023  Number of moles of NH3 = 8.63 x 1023/6.02 x 1023 =…

Q: Calculate the mass of 3.62 x 104 molecules of glucose (C,H1206).

A: Given that :Molecules of glucose (C6H12O6) = 3.62×1024 molecules Mass of glucose =?

Q: Mesitylene is a liquid hydrocarbon. Burning 0.650 g of the compound in oxygen gives 2.14 g of CO2…

A: Given information:Mass of mesitylene = 0.650 gMass of carbon dioxide = 2.14 gMass of water = 0.585…

Q: How many moles of H₂O can be formed from 7.44 × 10²³ molecules of NH₃ from the following equation? 4…

A: The species moles may be expressed in term of the algebraic relationship between the molecules…

Q: When 4.517 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.68 grams…

A:

Q: When 1.915 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 6.474 grams…

A: The general equation for the combustion reaction of hydrocarbon, CxHy, in the presence of oxygen is:…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.