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What is the electronic geometry of the following molecule? :: -P- -F:

What is the electronic geometry of the following molecule? :: -P- -F:

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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36.

**Question**: What is the electronic geometry of the following molecule? **Diagram Explanation**: The diagram shows a phosphorus atom (P) at the center with three fluorine atoms (F) bonded to it in a T-shaped arrangement. Each fluorine atom has three pairs of dots (lone pairs) around it, and the phosphorus atom also has two dots (a lone pair) on one side. **Options**: - ( ) Tetrahedral - ( ) Trigonal Pyramidal - (•) Trigonal Bipyramidal - ( ) Seesaw In this case, the correct answer is 'Trigonal Bipyramidal.' This represents the electronic geometry considering the lone pairs and bonds. The presence of lone pairs can affect the actual shape, which is 'T-shaped' for this molecule.
Transcribed Image Text:**Question**: What is the electronic geometry of the following molecule? **Diagram Explanation**: The diagram shows a phosphorus atom (P) at the center with three fluorine atoms (F) bonded to it in a T-shaped arrangement. Each fluorine atom has three pairs of dots (lone pairs) around it, and the phosphorus atom also has two dots (a lone pair) on one side. **Options**: - ( ) Tetrahedral - ( ) Trigonal Pyramidal - (•) Trigonal Bipyramidal - ( ) Seesaw In this case, the correct answer is 'Trigonal Bipyramidal.' This represents the electronic geometry considering the lone pairs and bonds. The presence of lone pairs can affect the actual shape, which is 'T-shaped' for this molecule.
Expert Solution
Step 1

Hybridization is defined as the no of atomic orbital redistribute their energy for archiving maximum valency.

no of hybrid orbital = no of sigma bonds + lone pair on the Centre atom.

for PF3

no of hybrid orbital =  3 sigma bonds + 1 lone pair.

                                = 4

so, hybridization = sp3    

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