**Question:**What is the electric field at a distance of 15 cm from an isolated point particle with a charge of 2 x 10^-9 C?**Answer:**E= ______ N/C**Explanation:**This question pertains to the calculation of the electric field generated by a point charge. The electric field \( E \) at a distance \( r \) from a point charge \( Q \) can be calculated using Coulomb's law, given by the formula:\[ E = \frac{k \cdot Q}{r^2} \]where:- \( k \) is Coulomb's constant (\( 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)),- \( Q \) is the point charge (\( 2 \times 10^{-9} \, \text{C} \)),- \( r \) is the distance from the charge (\( 0.15 \, \text{m} \)).Plugging in these values, the electric field can be calculated. The result should be expressed in units of Newtons per Coulomb (N/C).

Distance (r) = 15 cm = 0.15 mPoint charge (Q) = 2×10-9 CRequired:Electric field (E)

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What is the electric field at a distance of 15 cm from an isolated point particle with a charge of 2 x 10-⁹ C? i N/C

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