What is the effect applied electric field on the band structure of a conductor.
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- hw6 A current of I = 1.4 A is passing through a conductor with cross sectional area A = 4.5 × 10-4 m2. The charge carriers in the conductor, electrons, have a number density n = 9.7 x 1027 m-3. Calculate the numerical value of v, in m/s.I need some help solving this problem. I need to find the magnitude and direction of the current in this photo.Two parallel plates with an area of 3.0 cm2 are separated by a 2.5 mm thick dielectric with a constant of 4.70. If the potential difference between the plates is 120 V and the conduction current ic is 6.00 mA a) what is the charge (q) on each plate?
- Needs Complete solution with 100 % accuracy.Parallel conducting plates create nearly uniform fields that are used to accelerate and direct beams of electrons. Typically we would free the electrons from a surface by heating it up. One way is to run a current through a wire with resistance. The power dissipated in the wire causes it to increase its temperature to the point that it can radiate that power away, mostly carried off as light. The hot electrons escape the potential barrier at the surface and are "free" to use. Consider a source of electrons that is small, like a tiny hot filament. The electrons are freed from the surface but the positive charge they leave behind holds them in a cloud near the filament. Now we add another plate at voltage VV some distance dd away. We put a little hole in that plate to enable the electrons to zip on through. The experiment looks something like this. While they seem antiquated, the concept is still useful. It is the basis of modern X-ray tubes, and until only a few years ago all…A stream of electrons with a linear number density of 3.10 x 1011 electrons/meter are accelerated from rest by a 62.0-V potential difference applied across two parallel plates. The electrons then pass through an aperture in the high voltage plate and into a current collector where the beam current is measured. Note: The mass of an electron is 9.11 x 10-31 kg. (a) What is the magnitude of the electric field between the plates if they are 2.07 m apart? V/m (b) What is the final velocity of each electron? m/s (c) What is the beam current? A