What is the current through the battery when the switch SW1 is CLOSE and the switch SW2 is OPEN? Given the following circuitNOTE: THE AMMETER IS IN FACT LIKE A WIRE IN THE CIRCUIT - HAS NO RESISTANCEAM1SW1R4SW2BAT1R1R2R39 V929Ω

The problem is based upon the series and parallel connection. We know that an ammeter measured current and always connected in series and is having negligible resistance. To solve the problem, we have to calculate the equivalent resistance then need to apply Ohm's law to get the current in the batter.

Answered: What is the current through the battery…