What is the concentration of FeCl3 in a solution prepared by dissolving 35.0 g of FeCl3 in enough water to make 275 mL of solution? O 1.27 x 10³ M O 1.27 M O 0.785 M O 7.85 % 104 M
What is the concentration of FeCl3 in a solution prepared by dissolving 35.0 g of FeCl3 in enough water to make 275 mL of solution? O 1.27 x 10³ M O 1.27 M O 0.785 M O 7.85 % 104 M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Question:**
What is the concentration of FeCl₃ in a solution prepared by dissolving 35.0 g of FeCl₃ in enough water to make 275 mL of solution?
**Answer Choices:**
- \(1.27 \times 10^3\) M
- 1.27 M
- 0.785 M
- \(7.85 \times 10^{-4}\) M
In this question, you are asked to calculate the molarity (concentration) of a FeCl₃ solution. To find the concentration in moles per liter (M), you need to first convert the grams of FeCl₃ to moles, and then divide by the volume of the solution in liters. Here is how you can solve it:
1. **Convert the mass to moles:**
- Use the molar mass of FeCl₃ (which is approximately 162.2 g/mol).
2. **Convert volume to liters:**
- 275 mL = 0.275 L
3. **Calculate the molarity:**
- Molarity (M) = Moles of solute / Liters of solution
Explaining this calculation helps students understand how to determine molarity in practice.
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