What is the concentration (M) of the aqueous salt product in the reaction that occurs when 52.5 mL of 2.50 M FECI, solution is mixed with 72.8 mL of 2.70 M KOH solution? Assume the mixed volumes are additive.

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Question 7 of 8
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What is the concentration (M) of
the aqueous salt product in the
reaction that occurs when 52.5 mL
of 2.50 M FeCl3 solution is mixed
with 72.8 mL of 2.70 M KOH
solution? Assume the mixed
volumes are additive.
| M
1
2
3
4
C
7
9.
+/-
x 10 0
LO
00
Transcribed Image Text:Question 7 of 8 Submit What is the concentration (M) of the aqueous salt product in the reaction that occurs when 52.5 mL of 2.50 M FeCl3 solution is mixed with 72.8 mL of 2.70 M KOH solution? Assume the mixed volumes are additive. | M 1 2 3 4 C 7 9. +/- x 10 0 LO 00
Expert Solution
Step 1

Recall the reaction that will occur when FeCl3 and KOH is mixed together

       FeCl3aq + 3KOHaq  3KClaq + FeOH3sNow,milimoles=molarity×volume       52.5 mL of 2.50 M FeCl3=52.5 mL×2.50 M                                                =131.25 milimoles FeCl3       72.8 mL of 2.70 M KOH=72.8 mL×2.70 M                                              =196.56 milimoles KOH

Step 2

According to stoichiometry of reaction

      1 mole of FeCl3 reacts with 3 moles of KOHSo 196.56 milimoles of KOH will react with      =196.56 milimoles of KOH×1 mole of FeCl33 mole of KOH      =65.52 milimoles of FeCl3So FeCl3 is limiting reagent.

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